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2 years ago

Find the surface area of a cylinder with a height of 8 ft and a base radius of 5 ft.

Mathematics

1 answer:

Maksim231197 [3]2 years ago

7 0

Answer: 408.2 ft^2

Step-by-step explanation:

A=2πrh+2πr2

A=2(3.14)(5)(8)+2(3.14)(5)^2

A=6.28*40+6.28*25
A=251.2+157

A=408.2 ft^2

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Which equation is represented by the graph below?

Maksim231197 [3]

The correct equation is C y = In x + 4

6 0

3 years ago

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so

alexgriva [62]

Solution :

Let $p_1$ and $p_2$ represents the proportions of the seeds which germinate among the seeds planted in the soil containing $3\%$ and $5\%$ mushroom compost by weight respectively.

To test the null hypothesis $H_0: p_1=p_2$ against the alternate hypothesis $H_1:p_1 \neq p_2$ .

Let $\hat p_1, \hat p_2$ denotes the respective sample proportions and the $n_1, n_2$ represents the sample size respectively.

$$\hat p_1 = \frac{74}{155} = 0.477419$

$n_1=155$

$$p_2=\frac{86}{155}=0.554839$

$n_2=155$

The test statistic can be written as :

$$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}$

which under $H_0$ follows the standard normal distribution.

We reject $H_0$ at $0.05$ level of significance, if the P-value or if $|z_{obs}|>Z_{0.025}$

Now, the value of the test statistics = -1.368928

The critical value = $\pm 1.959964$

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

$=2 \times 0.085667$

= 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$ , so we fail to reject $H_0$ at $0.05$ level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the $\text{proportion}$ of the seeds that $\text{germinate differs}$ with the percent of the $\text{mushroom compost}$ in the soil.

8 0

2 years ago

How do I solve for a

qwelly [4]

Answer:

using the pythagoras theorem the answer is a=3

Step-by-step explanation:

basically in a right angled triangle a² + b² equals c². in this equation c is the number on the hypotenuse (the line opposite the right angle)

and 4 could be a or b it doesnt make a difference so I'll call it b.

because we have c² and b² we work backwards like this:

${5}^{2} - {4}^{2} = {a}^{2}$

${5}^{2} - {4}^{2} = 25 - 16 = 9$

because 9 is a², we must find the square root to find <em>a</em>

$\sqrt{9 } = 3$

so a equals 3

3 0

3 years ago

A sign at a bakery show s8 cookies for $10 and 12 cookies for $16. Find the unit price to the nearest cent (hundtreth) for each

Alja [10]

Answer:

8 cookies: 1 cookie =$1.25

12 cookies: 1 cookie =$1.33

Step-by-step explanation:

The formula for price per unit is : $\frac{price}{unit}$

Lets first work out the price per unit for the 8 cookies. You can do this by dividing the price of 10 by the amount of 8, this gives you $1.25. This means that the price per cookie is $1.25.

Now to work out the price per cookie for 12 cookies. You can do this by dividing the price of 16 by the amount of 12, this gives you $1.33. This means that the price per cookie for this offer is $1.33.

1) Divide 10 by 8.

$10/8=1.25$

2) Divide 16 by 12.

$16/12=1.33$

3 0

3 years ago

Resident of a small city voted on weather to allow a developer to build a shopping center. The number of votes in favor of the s

ycow [4]

19% of the voters were in Favor of building the shopping center.

<u>Step-by-step explanation</u>:

Number of votes in favor of the shopping center = 4,000
Number of votes against the shopping center = 17,000

Total voters in the city = number of votes in favor of the shopping center + number of votes against the shopping center.

Total voters = 4000 + 17,000 = 21,000.

Percentage= (No. of votes in favor of shopping center / total voters) $\times$ 100

⇒ (4000/21,000) $\times$ 100

⇒ (4/21) $\times$ 100

⇒ 19%

∴ 19% of the voters were in Favor of building the shopping center.

5 0

3 years ago