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SSSSS [86.1K]
2 years ago
10

Which choice below shows the following numbers in order from least to greatest?

Mathematics
1 answer:
vfiekz [6]2 years ago
5 0

Answer:

1/3, \sqrt{4}, π, \sqrt{16}, 8

Step-by-step explanation:

Simplifying or rounding complicated numbers to integers can help us order them.

  • Integer - an integer is any whole number, including zero, that can be negative or positive.

Simplifying Numbers

Numbers like 1/3 and 8 don't need to be simplified because they are commonly used and understood.

Both 4 and 16 are perfect squares. So, to simplify these numbers we can just solve.

  • \sqrt{4} = 2
  • \sqrt{16} = 4

There is no way to "solve" pi, but we can round it to an easier number. Technically, pi is irrational, so there is no way to write out the whole number. However, in this case, we can just round to the nearest whole number.

  • π ≈ 3

This means, in the order they appear, the simplified numbers are 2, 8, 4, 1/3, and 3.

Ordering the Numbers

From this point, they should be easy to order.

  • 1/3 is the smallest because it is the only number less than 1.
  • \sqrt{4} is next because it is equal to 2
  • π is third since it is only slightly above 3
  • \sqrt{16} is fourth since it is equal to 4
  • 8 is the largest number on the list.
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-8x+3=19

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X=2

I hope this helps.
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3 years ago
I need help asap 3x + 1 over 4y2
Blababa [14]
Ok so first, write down the equation. We know that x=3 and y=4. You just basically plug in the terms into the variables. So it would be 3(3)+1/4(4)^2. Simplify that equation and you should get your answer :)
7 0
3 years ago
What is the answer to this problem? 7(g+5)=105
Liono4ka [1.6K]

Answer:

g = 10

Step-by-step explanation:

Distribute 7 to the parentheses:

7(g + 5) = 105

7g + 35 = 105

Solve for g:

7g + 35 = 105

7g = 170

g = 10

So, the answer is g = 10

3 0
2 years ago
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25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
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Solve for s.<br> -7 = 7s + 28
Zinaida [17]

Answer:

s=  -5

Step-by-step explanation:

have a good day

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