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SSSSS [86.1K]
2 years ago
15

Construct the confidence interval for the population mean. c=. 95 x=6. 4 o=. 3 and n=42.

Mathematics
1 answer:
Damm [24]2 years ago
3 0

The confidence interval is (63.909, 64.0907).

The confidence interval of a population mean is found using the formula:

CI = x ± z(σ/√n), where CI is the confidence interval, x is the mean, z is the z-score corresponding to the confidence level, σ is the standard deviation, and n is the population size.

In the question, we are given the confidence level, c = 95%.

Z-score corresponding to this, z = 1.96.

The mean of the population, x = 6.4.

The standard deviation of the population, σ = 0.3.

The population size, n = 42.

Thus, using the formula, the confidence interval is:

CI = 6.4 ± 1.96(0.3/√42),

or, CI = 6.4 ± 0.09073037.

Thus, the confidence interval is (64 - 0.09073037, 64 + 0.09073037), or, (63.909, 64.0907).

Learn more about the confidence interval at

brainly.com/question/17097944

#SPJ4

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3 years ago
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c O
Bas_tet [7]

Answer:

  1. addition property of equality
  2. integers are closed to addition
  3. identity element
  4. multiplication property of equality
  5. commutative property of multiplication; reals are closed to multiplication; identity element

Step-by-step explanation:

<u>Given</u>:

  c/2 -5 = 7

  Step 1: c/2 -5 +5 = 7 +5

  Step 2: c/2 +0 = 12

  Step 3: c/2 = 12

  Step 4: 2(c/2) = 12(2)

  Step 5: c = 24

<u>Find</u>:

  The property that justifies each step of the solution.

<u>Solution</u>:

  Step 1: addition property of equality (lets you add the same to both sides)

  Step 2: integers are closed to addition

  Step 3: identity property of addition (adding 0 changes nothing)

  Step 4: multiplication property of equality

  Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality.  Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

8 0
4 years ago
Read 2 more answers
Charles can type 675 words in 9 minutes <br><br>how many words can he type in 13 minutes??<br>​
Gekata [30.6K]

Answer:

975

Step-by-step explanation:

6 0
3 years ago
Please help! acellus
ch4aika [34]

Answer:

The number that belongs <em>in</em> the green box is equal to 909.

General Formulas and Concepts:
<u>Algebra I</u>

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Trigonometry</u>

[<em>Right Triangles Only</em>] Pythagorean Theorem:
\displaystyle a^2 + b^2 = c^2

  • a is a leg
  • b is another leg
  • c is the hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given variables</em>.

<em>a</em> = 30

<em>b</em> = 3

<em>c</em> = <em>x</em>

<em />

<u>Step 2: Find </u><u><em>x</em></u>

Let's solve for the <em>general</em> equation that allows us to find the hypotenuse:

  1. [Pythagorean Theorem] Square root both sides [Equality Property]:
    \displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}

Now that we have the <em>formula</em> to solve for the hypotenuse, let's figure out what <em>x</em> is equal to:

  1. [Equation] <em>Substitute</em> in variables:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}
  2. <em>Evaluate</em>:
    \displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}

∴ the hypotenuse length <em>x</em> is equal to √909 and the number <em>under</em> the square root, our answer, is equal to 909.

___

Learn more about Trigonometry: brainly.com/question/27707750

___

Topic: Trigonometry

3 0
2 years ago
Use the graph of f at the right to complete each of the parts (a) through (h)
Maru [420]

<u><em>Answers:</em></u>

a. The domain of f is ]-∞ , ∞[

b. The range of f is [-4 , ∞[

c. f(1) = 5

d. The vales of x for which f(x) is -3 are 7 and 9

e. The points at which the graph crosses the x-axis are (6,0) and (10,0)

f. The point where the graph of f crosses the y-axis is (0,5)

g. The values of x for which f(x) < 0 are ]6 , 10[

h. f(-7) is positive

<u><em>Explanation:</em></u>

<u>Part a:</u>

The domain of the function refers to all the possible x-values that can be used as an input for this function.

Taking a look at the graph, we can see that the graph extends endlessly from both ends of the x-axis. This means that all x-values can be used as a domain for the function. In other words, the domain of the function is all the real numbers.

<u>In interval notation, this is written as:</u>

Domain = ]-∞ , ∞[

<u>Part b:</u>

The range of the function refers to all the possible y-values that can be used as an output for the function.

From the graph, we can note that the function extends endlessly in the direction of the positive y-axis while it stops at a value of -4 in the direction of the negative y-axis.

This means that the range of the function starts from -4 (included) and extends to positive infinity.

<u>In interval notation, this is written as:</u>

R = [-4 , ∞[

<u>Part c: </u>

f(1) means that we are looking for the output (the value of y) for which the input (the value of x) is 1.

From the graph, we start by searching for x=1 (first square edge after the origin) and then move vertically till we intersect the graph.

Doing this, we will find that the value of y at x=1 is 5

<u>Therefore:</u>

f(1) = 5

<u>Part d:</u>

f(x) = -3 means that the output value (the value of the y) for the certain input (value of x) is -3

To get the value of x, we go y=-3 and move horizontally till we intersect the graph.

<u>Doing this, we will find that</u> the value of y is -3 at x = 7 and x = 9

<u>Part e:</u>

The points where the graph crosses the x-axis are the points that have y-value equal to 0

<u>Checking the graph, we can note that</u> the function crosses the x-axis at two points which are (6,0) and (10,0)

<u>Part f:</u>

The point where the graph crosses the y-axis is the point that has x-value equal to 0

<u>Checking the graph, we can note that</u> the function crosses the y-axis at only one point which is (0,5)

<u>Part g:</u>

f(x) < 0 means that the output of the function (the y-value) is less than 0 (0 is not included)

Taking a look at the graph, we can note that the function has negative output on the interval from 6 (excluded) to 10 (excluded)

<u>In interval notation, this is written as</u> ]6 , 10[

<u>Part h:</u>

f(-7) means the output of the function (the y-value) at input (x-vale) equal to -7

From the graph, we can note that the function has a constant value of 5 starting from x=5 till -∞

<u>This means that</u>, at x=-7, the value of y is 5 which is a positive value

Hope this helps :)

6 0
4 years ago
Read 2 more answers
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