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grigory [225]
3 years ago
15

In Exercises 26-28, write an equation. Then solve.

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Answer:

The temperature outside is  75.6°F

Step-by-step explanation:

We are given the following in the question:

The temperature of dry ice = - 109.3°F

Let x be the temperature outside in Fahrenheit.

It is given that the temperature of dry ice  is 184.9°F less than  the outside temperature.

Thus, we can write the equation:

x - 184.9 = -109.3

Solving, the above equation, we get:

x - 184.9 = -109.3\\x = -109.3 + 184.9\\x = 75.6

Thus, the temperature outside is  75.6°F

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It costs $120 for 20 students to visit an aquarium. How much does it cost for 152 students? Set up a proportion to solve.​
nordsb [41]

Answer:

152 times 6=912

Step-by-step explanation:

$120 for every 20 students

it cost $6 for every 1 student

$6 times 152=912

5 0
3 years ago
Evaluating expressions k3+j
mrs_skeptik [129]
The answer is 3k+j since 3 cannot be multiplied after k.
3 0
3 years ago
WILL GIVE BRAINLIEST
Alja [10]

A. The pair of linear equations are: x + y = 55 and y = x + 25

B. Number of time she spend running everyday is: 15 minutes.

C. It is not possible.

<h3>How to Write a System of Linear Equations?</h3>

A system of equations consist of linear equations that have unknown variables whose values make the linear equations in the system true.

<u>Part A:</u> To write a pair of linear equations, do the following,

Let x represent the time Jackie runs

Let y represent the time Jackie dances

We are given that, Jackie runs and dances for a total of 55 minutes every day, therefore, the first linear equation would be:

x + y = 55 --> equation 1

We are also given that Jackie dances for 25 minutes longer than she runs, therefore, the second linear equation would be:

y = x + 25 --> equation 2

Therefore, the two pair of linear equations that shows the relationship between the number of minutes Jackie runs and dances everyday are:

x + y = 55

y = x + 25

Part B: Substitute y = (x + 25) into equation 1

x + y = 55 --> equation 1

x + x + 25 = 55

2x + 25 = 55

2x = 55 - 25

2x = 30

x = 15

Therefore, the number of time she spend running everyday is: 15 minutes.

Part C:

If she spent 45 minutes dancing (y = 45), and x = 15, substitute the values into x + y = 55 to find out if it is possible.

15 + 45 = 55

60 = 55 (not true)

Therefore, it is not possible.

Learn more about the system of equations on:

brainly.com/question/13729904

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8 0
2 years ago
3 decagrams = centgrams
notsponge [240]

Answer:

3,000

Step-by-step explanation:

Just multiply every decagram by 1,000

7 0
3 years ago
ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
  • cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
3 years ago
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