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Dmitriy789 [7]
2 years ago
8

Solve algebraically the simultaneous equations

Mathematics
1 answer:
Bess [88]2 years ago
8 0

Answer:waffle

Step-by-step explanation:

Basically ill tell you the answer if it says it helped you

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Copy and complete:<br> __:11= 1/3 :6
Aleksandr [31]

Answer:

11/18:11=1/3:6

Step-by-step explanation:

x:11=x/11 so

x/11=1/3/6

x /11=1/3*6

x=11/18

7 0
3 years ago
X^2-x-20 how do I write that in factored form
Rufina [12.5K]

Answer:

(x+4)(x-5)

Step-by-step explanation:

You need to find two numbers that multiply to be -20 but add up to be -1.

4 0
3 years ago
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Please help me i don’t have much long on this test
Len [333]

Answer:

C. 248 square meters

Step-by-step explanation:

2(10 x 6) + 2(10 x 4) + 2(6 x 4)

= 120 + 80 + 48

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3 years ago
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Identify the terms, coefficients, and constants in the expression. 7h + 3
dexar [7]

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Step-by-step explanation:


7 0
3 years ago
A group of 485 people take a canoe trip. They fill up all avalible canoes that each hold 3 people with 273 people. The rest of t
Jobisdone [24]
Answer:
3c=273
c=91
2c= 212
C= 106
c= 91+ 106= 197
so they will need 197 canoes total

Why:
So first you have to determine a set variable to represent the number of canoes, I chose C. Then you make an equation to represent the number of canoes 273 people will use if they group into 3's, from this I got 3c=273. Solve for C and get 91.
The remainder of the group which is 485-273= 212 will use canoes in groups of 2's. To represent this, 2c=212. Solve for C and get 106. Combine 106 and 91 to get the total number of canoes.
4 0
3 years ago
Read 2 more answers
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