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Dmitriy789 [7]
3 years ago
8

Solve algebraically the simultaneous equations

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:waffle

Step-by-step explanation:

Basically ill tell you the answer if it says it helped you

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Solve for x.<br><br> 3x - 13 = 2<br><br> (SHOW YOUR WORK)
Eddi Din [679]

3x-13=2

move -13 to the other side

sign changes from -13 to +13

3x-13+13=2+13

3x=2+13

3x=15

divide both sides by 3 to get x by itself

3x/3=15/3

cross out 3 and 3, divide by 3 and then becomes 1*1*x=x

x=15/3

x=5

answer:

x=5

7 0
3 years ago
Circle the table the represents a linear relationship.
nata0808 [166]
2nd one because it’s not a lot of big number I hope it helps
3 0
3 years ago
This is a double question. Part 1: 5(2x - 4) = 30. Solve for x Part 2: 5x + 3 - x + 2 = 41. Solve for x. I will mark Brainliest
Ainat [17]

Answer:

see below

Step-by-step explanation:

Part 1: 5(2x - 4) = 30.

Distribute

10x -20 = 30

Add 20 to each side

10x-20+20 =30+20

10x = 50

Divide by 10

10x/10 = 50/10

x =5

Part 2: 5x + 3 - x + 2 = 41

Combine like terms

4x +5 = 41

Subtract 5 from each side

4x+5-5 = 41-5

4x = 36

Divide by 4

4x/4 = 36/4

x = 9

3 0
3 years ago
Read 2 more answers
What is the angle in part c? Thank you.
Anton [14]
It looks like an equilateral triangle if I am correct then angle C equals 60 degrees
7 0
3 years ago
Please help!! i have limited time
Phantasy [73]

Answer:

Number 1

Step-by-step explanation:

The median in number 1 is 13 and the range for number 1 is also thirteen so it has to be it.

5 0
3 years ago
Read 2 more answers
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