The addison see to the horizon at 2 root 2mi.
We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.
We have to find the how much farther can addison see to the horizon
<h3>Which equation we get from the given condition?</h3>

Where, we have
d- the distance they can see in thousands
h- their eye-level height in feet
For Kaylib

For Addison h=85(1/3)

Subtracting both distances we get

Therefore, the addison see to the horizon at 2 root 2mi.
To learn more about the eye level visit:
brainly.com/question/1392973
Answer:
option C.
Step-by-step explanation:
since the graph y = 6x is shrunk by a factor of ½
it becomes y = 3x
to find one coordinate of this graph we put x = 1 so that we get y = 3
so one point we have is (1, 3).
and the other point is origin
[ for if you keep x = 0 then 3 × 0 = 0 so y comes 0 too.]
now this graph is translated 9 units in the negative y direction
so the point that initially was (0, 0) now becomes (0, -9).
we see that the only graph passing thru (0, -9) is C.
so the answer is <u>option C.</u>


Answer:
$0.25
Step-by-step explanation:
To find unit rate divide number of shirts by cost of package
$2.00/8 = $0.25
So each individual golf tee costs $0.25
Answer:
infinite solutions
Step-by-step explanation:
Given
3(8m + 5) = 4(6m + 7) - 13 ← distribute parenthesis on both sides
24m + 15 = 24m + 28 - 13 , that is
24m + 15 = 24m + 15
Since both sides are equal then any real value of x makes the equation true.
Thus there are an infinite number of solutions
Answer:
x = 7.55
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2 +b^2 = c^2
where a and b are the legs and c is the hypotenuse
a^2 +8^2 = 11^2
x^2 +64 = 121
Subtract 64 from each side
x^2 +64-64 = 121-64
x^2 =57
Take the square root of each side
sqrt(x^2) = sqrt(57)
x = 7.549834435
To the nearest hundredth
x = 7.55