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Verdich [7]
1 year ago
14

One year, the population of a city was 352,000. Several years later it was 337,920.

Mathematics
1 answer:
kvasek [131]1 year ago
8 0

hi

here is  the  method :

you take  Value 1  and Value 2

And you do :   ( Value 2 - Value 1)  / (Value 1 )    * 100

Here we have :    Value 1 = 352 000

                            Value 2 =  337 920

So now we apply :

( 337 920 - 352 000 )  /  ( 352 000)   * 100 =  -4  

Population decreased by by  4 %

You can also make :  

352 000 * X = 337 920

                 X =  337 920 / 352 000

                 X = 0.96

if  the multiplier is  0.96 ,  it's mean that we lost  1 -0.96 = 0.04  

which mean  - 4%

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a. the cost of a call for six minutes is 0.70.

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<h3>How to find the cost of each call ?</h3>

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a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

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