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notsponge [240]
2 years ago
7

What is the name given to the portion of the electrocardiogram between two waves?.

Physics
1 answer:
olya-2409 [2.1K]2 years ago
3 0

Segment

The space between two waves is known as a segment in an ECG. Beginning at the end of the P wave and ending at the beginning of the QRS complex is the PR segment. Beginning at the end of the QRS wave and ending at the beginning of the T wave is the ST segment.

<h3>What is ECG ?</h3>

An electrocardiogram (ECG) is a quick test that can be used to examine the electrical activity and rhythm of your heart. The electrical signals that your heart beats out each time it beats are picked up by sensors that are affixed to your skin.

  • A test that captures the electrical activity of the heart is called an electrocardiogram (ECG). The ECG shows what is occurring in various heart regions and aids in identifying any issues with heart rate or rhythm.

Learn more about ECG here:

brainly.com/question/7172728

#SPJ4

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Also a plasma does not contain neutral elements (atoms) or (neutral) molecules, but Ionized atoms and/or molecules and free electrons.

Thus the good answer is d) 

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The answer is 222.1 K

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Most of the world uses fossil fuels because they are
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hello the options to your question is missing below are the options

culture

heredity

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answer : social environment

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6 0
3 years ago
A series AC circuit contains a resistor, an inductor of 220 mH, a capacitor of 5.50 μF, and a generator with ΔVmax = 240 V opera
ki77a [65]

Answer:

Xl=wL=69.11503383 ohm

Xc=\frac{-1}{wC}= -578.7452476 ohm

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

R=2.223915928 kilo-ohm

\alpha = -12.90698798 centigrades

Explanation:

L=220*10^-3

C=5.50*10^-6

Vmax=240V

Imax=140*10^-3

w=2\pi f=2\pi *50=314.1592654

The capacitive reactance is given by:

Xc=\frac{-1}{wC}=-578.7452476 ohm

Now,  The inductive reactance is given by:

Xl=wL=69.11503383 ohm

By the ohm´s law, the electrical impedance is:

V=IZ

So

Z=\frac{V}{I}

Z=\frac{240}{140*10^-3}=1.714285714 kilo-ohm

The total impedance is:

Z=R+jX\\\\ (*)

Where X is the total reactance given by:

X=Xl+Xc=69.11503383-578.7452476=-509.6302138

Let´s calculate the real part of Z using (*):

R=1714.285714+509.6302138

R=2.223915928 kilo-ohm

Finally the angle between the current and the voltage is equal to the impedance angle:

\alpha=arctan(\frac{-509.6302138}{2223.915928})

\alpha =-12.90698798 centigrades

8 0
3 years ago
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