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leonid [27]
4 years ago
7

Half-Life refers to radiation levels true or false

Physics
1 answer:
o-na [289]4 years ago
3 0

Answer:

True

Explanation:

Because <em><u>half</u></em><em><u> </u></em><em><u>life</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>length</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>time</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>takes</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>the</u></em><em><u>,</u></em>half of the radioactive atoms of a specific radionuclied to decay.

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Consider this situation: A rope is used to lift an actor upward off the stage. Of the forces listed, identify which act upon the
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4 years ago
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In a particular television picture tube, the measured beam current is 23.3 µA . How many electrons strike the tube screen every
zysi [14]

Answer:

Explanation:

Given that

Beam current (i)=23.3µA

And the time to strike(t)=28s

Also, a fundamental charge e=1.602×10^-19C

Then, the charge quantity is given as,

q=it

Then, q=23.3×10^-6×28

q=6.524×10^-4C

Also, the number of electron N is given as

q=Ne

Therefore, N=q/e

So, N=6.524×10-4/1.602×10^-19

N=4.072×10^15

There are 4.072×10^15 electrons strike the tube screen every 28 s.

7 0
3 years ago
The driver of a 1750 kg car traveling on a horizontal road at 110 km/h suddenly applies the brakes. Due to a slippery pavement,
Alexeev081 [22]

Answer: a=-2.4525 m/s^2

d=s=190.3 m

Explanation:The only force that is stopping the car and causing deceleration is the frictional force Fr

Fr = 25% of weight

W=mg

W=1750*9.81

W=17167.5

Hence

Fr=\frac{25}{100} * -17167.5\\\\Fr=-4291.875 N

Frictional force is negative as it acts in opposite direction

According to newton second law of motion

F=ma

hence

a=Fr/m

a=-4291.875/1750\\a=-2.4525

given

u= 110 km/h

u=110*1000/3600

u=30.55 m/s

to get t we know that final velocity v=0

v^2=u^2+2as\\0=30.55^2-2*2.4525*s\\s=190.34m

3 0
3 years ago
g An arrow is shot straight up in the air at an initial speed of 15.5 m/s. After how much time is the arrow moving downward at a
Sati [7]

Answer:

2.11 seconds

Explanation:

We use the kinematic equation for the velocity in a constantly accelerated motion under the acceleration of gravity (g):

v_f=v_i-g*t\\-5.2 = 15.5 - 9.8\,t\\9.8 \,t= 15.5 + 5.2\\t = 20.7/9.8\\t = 2.11 \,\,sec

5 0
3 years ago
If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w
Elina [12.6K]
The answer is letter C.

Weight (on Earth) is the force due to the mass of Earth attracting whatever mass is subject of discussion.

The force of attraction between any two masses is called Newton's Law of Universal Gravitation:

G \frac{m_1m_2}{d^2}

G is simply a given constant.

If we're at the surface of Eath, m_1 refers to the mass of the Earth, m_2 to the mass of whatever is on the surface of Earth, and d to the radius of Earth. 

Normally, we define a constant g to be equal to G \frac{M}{r^2}; in which M is the mass of Earth and r the radius of earth; g happens to be around 9.8.

By that, we adapt the Law of Universal Gravitation to objects on the surface of Earth, we call that force Weight.

W=mg

As you can see, weight is directly proportional to mass, more mass implies more weight.
8 0
4 years ago
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