A cubical furnace with external dimensions of 0:6 m is constructed from reclay brick. If the wall thickness is 40 mm, the inner surface temp 630C , and the outer surface temperature is 70C, calculate the heat loss (in kW) from the furnace.
1 answer:
Answer:
Explanation:
surface area of furnace = 6 x .6²
=2.16 m²
Rate of heat loss = k A ( θ₂ -θ₁ ) / t where k is coefficient of thermal conductivity , A is surface involved , θ₂ -θ₁ is temperature difference and t is thickness .
For fire clay thermal conductivity
= .05 W / m . K
.05 x 2.16 x ( 630 - 70 ) / .04
= 1512 W
= 1.5 kW .
You might be interested in
9.8 ms^-2 is acceleration
What part of the bacterial cell helps it stick to surfaces
Answer:
2.04m
Explanation:
PE=mgh
h= PE/mg
h= 40/2(9.82)
h=40/19.64
h=2.04
D)
Explanation:
Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity
Answer:
Kelvin
Explanation:
fact as per the guideline given
