Explanation:
It is given that,
Length of the string, l = 2 m
Mass of the string,
Hanged mass in the string,
1. The tension in the string is given by :
T = 1.96 N
2. Velocity of the transverse wave in the string is given by :
m = M/l
v = 28 m/s
Hence, this is the required solution.
Answer:
-2π ≤ ∅ ≤ 3π/2
0 ≤ ∅ ≤ π/2
Explanation:
In simple harmonic motion, the displacement and velocity vectors are as follows:
where ∅ is the phase angle. At t = 0, the initial displacement and velocity are
According to two equations, we need to find the ∅ values which makes both cosine and sine terms positive.
So, ∅ is in the range: [-2π, -3π/2] and [0,π/2]
The volume of the room is the product of its dimensions:
Now, from the equation
where d is the density, m is the mass and V is the volume, we deduce
So, multiply the density and the volume to get the mass of air in the room.