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telo118 [61]
2 years ago
8

How many grams are NaCl are required to prepare 200 mL of a 3.10 M solution?

Biology
1 answer:
rodikova [14]2 years ago
6 0

The mass (in grams) of NaCl required to prepare the solution is 36.27 g

<h3>What is molarity?</h3>

Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of NaCl</h3>
  • Volume = 200 mL = 200 / 1000 = 0.2 L
  • Molarity = 3.1 M
  • Mole of NaCl =?

The mole of NaCl in the solution can be obtained as follow:

Molarity = mole / Volume

Cross multiply

Mole = Molarity x Volume

Mole of NaCl = 3.1 × 0.2

Mole of NaCl = 0.62 mole

<h3>How to determine the mass of NaCl </h3>

We can obtain the mass of NaCl needed to prepare the solution as follow:

  • Molar mass of NaCl = 58.5 g/mol
  • Mole of NaCl = 0.62 mole
  • Mass of NaCl = ?

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of NaCl = 0.62 × 58.5

Mass of NaCl = 36.27 g

Learn more about molarity:

brainly.com/question/15370276

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