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Alisiya [41]
2 years ago
8

Plases help help help help

Mathematics
2 answers:
prohojiy [21]2 years ago
8 0
Ummmmmm I think it’s 10
vodka [1.7K]2 years ago
4 0
Im also guessing that it’s ten but im making and educated guess
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For every 1/4 mi Pascal walks Lucien runs 2/3 mi. How many miles does Pascal walk for every 1 mi Lucien runs? Write your answers
attashe74 [19]

Answer:

Step-by-step explanation:  The answer is 0.5

7 0
3 years ago
What is the product in simplest form.
Alex787 [66]

Answer:

a)

-  \frac{9}{22}

7 0
2 years ago
What is the greatest common factor of 90, 126, 180 and 990?
mylen [45]

9514 1404 393

Answer:

  18

Step-by-step explanation:

90 = 18·5

126 = 18·7

180 = 18·10

990 = 18·55

The greatest common factor of these numbers is 18.

__

<em>Comment on the GCF</em>

It can be useful to know Euclid's algorithm for finding the GCF:

  1. Determine the remainder from dividing the larger number by the smaller.
  2. If the remainder is zero, the smaller number is the GCF. If the remainder is non-zero, use it to replace the larger number and repeat from step 1.

For example, 126 mod 90 = 36; 90 mod 36 = 18; 36 mod 18 = 0, so 18 is the GCF of 126 and 90. (The modulo function 'mod' returns the remainder from division.)

3 0
2 years ago
PLEASE ANSWER QUICK!!
Citrus2011 [14]

Answer:

A)  B is greater

B) when C = 21, A = 5 and B = 15

C) A must be 0, 5, or 12 for C to be greater than B

Step-by-step explanation:

A)  when a = -3, c = -20 and b = 4(-3)-5 so B = -17

B) when c = 21, a = 5 and b = 4(5)-5 so B = 15

C) C is greater than B when a = 0, 5, and 12

when a = 0, b = 4(0)-5 or -5

when a = 5, b = 4(5)-5 or 15

when a = 12, b = 4(12)-5 or 43

3 0
2 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
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