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Elis [28]
3 years ago
12

BRAINLIESTT ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
Levart [38]3 years ago
3 0

Answer:

\boxed{\bold{y\le \:-\frac{1}{3}}}

Explanation:

Multiply both sides by -1 (Reverse inequality)

\bold{\left(-3\left(5y-4\right)\right)\left(-1\right)\le \:17\left(-1\right)}

Simplify

\bold{3\left(5y-4\right)\le \:-17}

Divide both sides by 3

\bold{\frac{3\left(5y-4\right)}{3}\le \frac{-17}{3}}

Simplify

\bold{5y-4\le \:-\frac{17}{3}}

Add 4 to both sides

\bold{5y-4+4\le \:-\frac{17}{3}+4}

Simplify

\bold{5y\le \:-\frac{5}{3}}

Divide both sides by 5

\bold{\frac{5y}{5}\le \frac{-\frac{5}{3}}{5}}

Simplify

\bold{y\le \:-\frac{1}{3}}

Graphed solution below

(You would place the dot on the first dot left of the 0, then continue to the left.)

vesna_86 [32]3 years ago
3 0

Answer:

\large\boxed{y\leq-\dfrac{1}{3}\to y\in\left(-\infty,\ -\dfrac{1}{3}\right>}

Step-by-step explanation:

-3(5y-4)\geq17\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(-3)(5y)+(-3)(-4)\geq17\\\\-15y+12\geq17\qquad\text{subtract 12 from both sides}\\\\-15y+12-12\geq17-12\\\\-15y\geq5\qquad\text{divide both sides by (-15)}\\\\\text{when you multiply or divide both sides of an inequality}\\\text{ by a negative number, you must flip the inequality sign}\\\\\dfrac{-15y}{-15}\leq\dfrac{5}{-15}\qquad\text{simplify}\\\\y\leq-\dfrac{5:5}{15:5}\\\\y\leq-\dfrac{1}{3}

<, > - open circle

≤, ≥ - closed circle

<, ≤ - draw the line to the left

>, ≥ - draw the line to the right

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