1/2t + 25; -10 PLEASE HELP

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

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Which represents where f(x) = g(x)? A) f(4) = g(4) and f(0) = g(0) B) f(–4) = g(–4) and f(0) = g(0) C) f(–4) = g(–2) and f(4) =

saul85 [17]

Answer:

B. f(-4) = g(-4), and f(0) = g(0)

Step-by-step explanation:

We are given two functions that have been graphed already. The points on the coordinate plane where the curve of g(x) intercepts that of f(x), are the values of x for each function, that would give us the same output (y).

Thus, for f(x) intercepts g(x) at the point where x = -4, y = 4.

Also, f(x) and g(x) intercepts at the point where x = 0, y = 4.

Therefore, the correct answer is f(-4) = g(-4), and f(0) = g(0)

6 0

3 years ago

- ( x - 1 ) = -4x - 2

7nadin3 [17]

Answer:

x=-1

Step-by-step explanation:

1. Remove the parenthesis

-x + 1 = -4x - 2

2. Get x alone

-x + 1 = -4x - 2

+1x +1x

1=-3x - 2

+2 +2

3=-3x -3x/-3= x 3/-3 = -1

x=-1

3 0

2 years ago

Approximately how much more quickly (in mph) does a pilot traveling 400 mph and rising at an angle of 30o gain altitude versus a

REY [17]

We can find the height of the altitude by the ratio of sin. See my attachment.
sin of angle = side in front of the angle / hypotenuse
sin x = height/distance

If the two pilot is rising in an hour, then the first distance is 400 miles, the second distance is 300 miles.

Find the height of first pilot
height/distance = sin x
height/400 = sin 30°
height = sin 30° × 400
height = 1/2 × 400
height = 200

Find the height of second pilot
height/distance = sin x
height/300 = sin 40°
height = sin 40° × 300
height = 0.642 × 300
height = 192

So the first pilot traveling 400 mph with 30° is more quickly to reach high altitude than the second pilot traveling 300 mph with 40°