Hello,
1)
Let's put some name of vertex:
A with angle A=45°
B with angle B=90°
C The 3 vertex of the triangle of left.
AC=9 , y=AB=BC
With Pythagore, we can say: y²+y²=9²==>2y²=81===>y=9/√2=9√2/2
The other triangle is BDC: cos(60°)=x/y==>x=y*1/2=9√2/4
2)
Let's give some names:
A with angle A=60°
B with angle B=90
C the 3th vertex of the left triangle.
AB=10, BC=y
tan 60°=y/10=sin(60°)/cos(60°)=(√3/2)/(1/2)=√3==>y=10√3
D is the 3 th vertex of the right triangle.
We use Pythagore: y²+y²=x²
x²=2*(10√3)²===>x=10*√6
The difference of the two temperatures is 92. This is because 90-92=-2. I hope this can help you.
Answer:
30 + 5<em>d</em> ≥ 120
Step-by-step explanation:
One ticket costs $120 and she already has $30 saved up so the money she makes by dogwalking added to the $30 has to be equal to or greater than 120
- 30 for the <u>amount she saved up</u>
- 5<em>d</em> where <u><em>d</em></u><u> stands for the number of days she walks dogs </u>
- Make this information into one part of the inequality: 30+5<em>d</em>
- Then this has to be greater than or equal to 120 so:
<u>30+5</u><em><u>d</u></em><u>≥120</u>
Hope this helps!
5x^2(3x-2)
5x^2 multipled 3x -5x^2 multipled -2
15x^2-10
