Answer: so i think for part a , the first term is a subscrpit 0 which is 10. Then the formula for any term in the sequence is Ao x R ^n. So R =2 so
1st term = 10 ( 2^0)= 1
2nd term = 10 (2^1) =20
3rd term = 10 (2^2)= 40
4th = 80
5th = 160
Part B
The limit as n approaches infinity for a sub n when R is 0, 1 and 2. THE LIMIT FOR R of 0, 1 and 2 is infinity.
Part C...i will have to research...sorry
Step-by-step explanation:
Answer:
$1000
Step-by-step explanation:
We can form an equation for Clayton's account: C = 500 + 10x
We can form an equation for Clayton's account: J = 400 +12x
(where x is the number of days)
When the two accounts will contain the same amount, it means: C = J
<=> 500 + 10x = 400 +12x
<=> x =50
After 50 days, there accounts will be balance. Then, we substitue x into any of the 2 equation to find out the amount: 500 + 10(50) = $1000
Complete the square by adding the square of half of four to both sides (4)
x^2+y^2-4y+4=4
x^2+(y-2)^2=4
