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Komok [63]
2 years ago
11

What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1

Mathematics
1 answer:
aleksandr82 [10.1K]2 years ago
7 0

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

            [ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis  = 2b

According to the question k = 2, h = -1, a = 4, b = 12

Length of the conjugate axis = 2b = 2 * 12  = 24

Learn more about hyperbola here :

brainly.com/question/3351710

#SPJ9

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Given that √5 = 2.24 and √50= 7.07 , find <br> √500 and √0.5
sineoko [7]

Answer:

see explanation

Step-by-step explanation:

using the rules of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

\sqrt{\frac{a}{b} } ⇔ \frac{\sqrt{a} }{\sqrt{b} }

then

\sqrt{500}

= \sqrt{100(5)}

= \sqrt{100} × \sqrt{5}

= 10 × 2.24

= 22.4

-------------------------------

\sqrt{0.5}

= \sqrt{\frac{50}{100} }

= \frac{\sqrt{50} }{\sqrt{100} }

= \frac{\sqrt{50} }{10}

= \frac{7.07}{10}

= 0.707

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2 years ago
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alekssr [168]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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Solve for y in the given equation 2y - 24 = 14y <br> Answer are <br><br> 8y <br> -8y<br> -2 <br> 2
ArbitrLikvidat [17]

Answer:

y = -2

Step-by-step explanation:

First, we subtract 2y on both sides:

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Then, we divide 12 on both sides:

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And we're done ^^ hope this helps!

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Answer:

If 2m is the radius, the diameter is 4 meters.

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The answer is A. 840
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