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aleksandrvk [35]
3 years ago
9

The exchange rate is £1 =$1.55

Mathematics
1 answer:
natta225 [31]3 years ago
7 0
£1=$1.55
£720=$1116
50×22=1100
this is the maximum because you if you add another $20, it would be too much
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An arithmetic sequence has this recursive formula:
Marianna [84]

Answer:

Option D is the correct option.

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5 0
3 years ago
You found the prime factorization of the number 73 explain how you can check your answer
antoniya [11.8K]

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Explanation:

You can check your answer by making sure that each of the primes you found is actually a prime. (Compare to a list of known primes, for example.) After you have determined your factors are primes, multiply them together to see if the result is 73. If so, you have found the correct prime factorization.

__

<em>Additional comment</em>

73 is prime, so its prime factor is 73.

  73 = 73

4 0
3 years ago
The standard deviation of the data set is 2.3. Compute the variance to the nearest hundredth. 2,2,2,3,5,5,6,7,8
Arada [10]
The standard deviation is the square root of the variance...so that means the variance is the standard deviation squared.

2.3^2 = 5.29 <===
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3 years ago
Mia's soccer coach told her to keep track of how much water she drinks. Yesterday she drank 18 ounces with breakfast, 21 ounces
igor_vitrenko [27]
Yes, 82 ounces is the correct answer.
6 0
3 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
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