Answer:
15.71
Step-by-step explanation:

now, a function may well be continuous, but it may not be differentiable.
graph wise, differentiability means, a smooth curve, with no abrupt spikes or drops or cuts.
so for this piece-wise to be differentiable, the subfunctions must meet at junctions smoothly, with no abrupt changes, so mx + b, must blend in with x³ smoothly.
now, that can only occur if mx + b has the same slope as x³ at that point where they meet. The point where they meet is at x = 1, well, let's check what is the slope of x³ at x = 1.
![\bf \cfrac{d}{dx}[x^3]\implies \left. 3x^2\cfrac{}{}\right|_{x=1}\implies 3(1)^2\implies 3](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bd%7D%7Bdx%7D%5Bx%5E3%5D%5Cimplies%20%5Cleft.%20%203x%5E2%5Ccfrac%7B%7D%7B%7D%5Cright%7C_%7Bx%3D1%7D%5Cimplies%203%281%29%5E2%5Cimplies%203)
therefore "m" for mx+b, must be 3 then.
now, what's the value of x³ at x = 1? well is just (1)³, which is 1.
so for 3x + b, when x = 1, it must also equals 1 as well, that way it meets x³, thus
3x + b
3(1) + b = 1
b = -2
check the graph below.
Answer:
7%
Step-by-step explanation:
Given the following :
Total Number of cards left in deck = 10
Number of hearts left in deck = 3
Probability = (required outcome / Total possible outcomes)
Required outcome = hearts card in deck
Two cards are to be dealt to Satara without replacement :
Probability of 1st card being hearts :
P(1st card being hearts) = required outcome / Total possible outcomes
P(1st card being hearts) = 3 / 10
Probability of 2nd card being hearts :
Since it is without replacement :
Required outcome = (3 - 1). = 2
Total possible outcomes = (10 - 1) = 9
P(2nd card being hearts) = 2 /9
Probability of the two cards being hearts :
(3 / 10 × 2/9) = 6 /90 = 0.0666
0.06666 × 100% = 6.66%
= 7% (nearest whole number)
Answer:
A and c
Step-by-step explanation:
multiply the 3 to both parts of equation
Answer:

Step-by-step explanation:
Given
ID Card of 5 digits
Possibly Digits = {0,1...,9}
Required
Probability that a card has exact number 94213
First, we have o determine the total possible number of ID card numbers
Let the card number be represented by ABCDE
Given that repetition of digits is not allowed;
<em>A can be any of 10 digits</em>
<em>B can any of the remaining 9 digits</em>
<em>C can be any of the remaining 8 digits</em>
<em>D can be any of the remaining 7 digits</em>
<em>E can be any of the remaining 6 digits</em>
<em />
Total number of cards = 10 * 9 *8 * 7 * 6
Total = 30240
Provided that the card number is generated at random; each card number has the same probability of 
Hence, the probability of having 94213 is 