Given:
The expression is:
To find:
Part A: The expression using parentheses so that the expression equals 23.
Part B: The expression using parentheses so that the expression equals 3.
Solution:
Part A:
In option A,
[Using BODMAS]
In option B,
[Using BODMAS]
In option C,
In option D,
[Using BODMAS]
After the calculation, we have and .
Therefore, the correct options are B and D.
Part B: From part A, it is clear that
Therefore, the correct option is C.
If 1 inch = 1 foot then 1 foot = 1 inch.
With this, you can make a ratio of 1 foot:1 inch, or 1:1.
Starting with the first dimension, 27 feet, just change the 1 to 27 in the ratio.
27:?
To find how many inches this is in the scale drawing, find how much 1 had to be multiplied by to get to 27. This is 27, since anything times 1 is itself.
Just multiply the other side by 27 as well to get the answer for the first dimension.
1 • 27 = 27
So 27 feet = 27 inches in the scale drawing.
Now do the same for the second dimension.
1:1
20:?
1 • 20 = 20
20:20
The answer is that the scale drawing has dimensions of 27 inches by 20 inches if 1 inch = 1 foot is the scale
If I am reading this right, the final total after adding the 55% markup rate should be $159.65.
If the height was 10, then the volume of the cube would be 1000 because you find volume you must multiply the length*width*height and the value of those three is 10.
Now since volume is 1000 and the volume of a 2in cube is 8 (again, lwh=V) you can divide 1000 by 8 and you would get 125. So that means 125 2in cubes can fit inside the bigger cube.
If the volume of this cube were 750in^3 and you had to find the height, you would use the Volume formula again:
l*w*h=V
10*10*h=750
20h=750
((divide both sides of the equation by 20 to find the value of h))
h=37.5
If the surface area of the cube were 680in^2 then you would use the surface area formula to find the value of h:
(2(lw))+(2(lh))+(2(wh))=A
(2(10*10))+(2(10h))+(2(10h))=680
200+20h+20h=680
subtract 200 from both sides of the equation:
40h=480
divide both sides by 40 to get the value of h:
h=12
