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natka813 [3]
2 years ago
11

Two fair coins are to be tossed once. For each head that results, one fair die is to be rolled. What is the probability that the

sum of the die rolls is odd
Mathematics
1 answer:
Lera25 [3.4K]2 years ago
3 0

There is a 1/4 chance of no heads, and therefore no dice. The sum of no dice is 0, which is even.

There is a 1/2 chance of one head, and therefore one die. For one die, there is a 1/2 chance of landing on an odd total 1,3,5.

There is a 1/4 chance of getting two heads, and therefore two dice. There are an equal number of possibilities giving even and odd, so there is again a 1/2 chance of landing on an odd total.

So in total, we have total probability

1/4⋅0+1/2⋅1/2+1/4⋅1/2=3/8.

The ratio of the number of results in an exhaustive set of similarly probable outcomes that produce a given occasion to the entire quantity of feasible results. b : a branch of arithmetic worried with the observe of probabilities.

The chance of an event can be calculated through possibility system by way of truely dividing the favorable variety of results by means of the entire wide variety of feasible outcomes.

Many events cannot be anticipated with total actuality. we will are expecting simplest the danger of an event to occur i.e. how possibly they're to appear, the usage of it.

Learn more about Coin Probability here brainly.com/question/10837034

#SPJ4

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The sum of the digits of a two-digit number is 11. When the digits are reversed, the new number is 27 more than the original num
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Answer: 47

Step-by-step explanation: To solve this problem, let's use <em>t</em> to represent our tens digit and <em>u</em> to represent our units digit so that the value of our number can be represented as 10<em>t</em> + <em>u</em>.

If we represent the value of our number as 10<em>t</em> + <em>u</em>, the value of the number with the digits reversed can be represented as 10<em>u</em> + <em>t</em>.

Since the first sentence states that the sum of the digits of a two-digit number is 11, that's <em>t </em>+<em> u</em> = 11.

Reading through our second sentence, when the digits are reversed, the new number is 27 more than the original number, that's 10<em>u</em> + <em>t</em> "is" which means equals 27 more than the original number that's 10<em>t </em>+ <em>u</em> + 27.

So 10<em>t</em> + <em>u</em> = 10<em>t</em> + <em>u</em> + 27.

Before solving this system however, let's rearrange our second equation so that the t's and u's are on the same side by subtracting 10<em>t</em> and <em>u</em> from both sides to get 9<em>u</em> - 9<em>t</em> = 27 and when we rewrite our first equation above it, instead of writing it as <em>t</em> + <em>u</em> = 11, let's write it as <em>t</em> + <em>u</em> = 11 so that our u's and t's will match up in the system.

To solve this system, let's use addition so multiply the top equation by 9 to get 9<em>u </em>+ 9<em>t</em> = 99 and 9<em>u</em> - 9<em>t</em> = 27 so that when we add the equations together the t's cancel and we get 18<em>u</em> = 126. Dividing both sided by 18, <em>u </em>= 7.

To find <em>t</em>, plug 7 back in for <em>u</em> in our first equation to get <em>t</em> + 7 = 11. Subtract 7 from both sides and <em>t</em> = 4.

Since our tens digit is 4 and our units is 7, our number must be 47.

I have also attached my work on a whiteboard.

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