What value of x satisfies this equation? log2 (6x – 8) – log, 2^8=1 The value of x is?

1 answer:

Maslowich2 years ago

3 0

Answer:

$x=4$

Step-by-step explanation:

$log_2(6x-8)-log_2(8)=1\\\\log_2(\frac{6x-8}{8})=1\\ \\\frac{6x-8}{8}=2\\ \\6x-8=16\\\\6x=24\\\\x=4$

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