<span>The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3.</span>
Answer:
B. Friction with air also affects the fall of the object.
Explanation:
The limitation of this experimental design is that friction with air also affects the fall of the object.
- Therefore, it is difficult to measure effect of gravity on falling objects.
- Air resistance cause friction in the movement of an object falling.
- Frictional force resists the motion of an object subject to free fall.
Therefore, the experiment will be biased due to the influence of the frictional force.
If it makes 50 complete back-and-forth wiggles in 1 second, then its frequency is <em>50 Hz</em>.
Answer:
A) μ = A.m²
B) z = 0.46m
Explanation:
A) Magnetic dipole moment of a coil is given by; μ = NIA
Where;
N is number of turns of coil
I is current in wire
A is area
We are given
N = 300 turns; I = 4A ; d =5cm = 0.05m
Area = πd²/4 = π(0.05)²/4 = 0.001963
So,
μ = 300 x 4 x 0.001963 = 2.36 A.m².
B) The magnetic field at a distance z along the coils perpendicular central axis is parallel to the axis and is given by;
B = (μ_o•μ)/(2π•z³)
Let's make z the subject ;
z = [(μ_o•μ)/(2π•B)] ^(⅓)
Where u_o is vacuum permiability with a value of 4π x 10^(-7) H
Also, B = 5 mT = 5 x 10^(-6) T
Thus,
z = [ (4π x 10^(-7)•2.36)/(2π•5 x 10^(-6))]^(⅓)
Solving this gives; z = 0.46m =
Answer:
The amount of time needed for this heating to occur is 126.25 min
Explanation:
Given;
power required to heat the room = 2kW
volume of the room = 5 m X 5 m X 6 m = 150 m³
atmospheric pressure at sea level = 101 Kpa
Internal energy available in this room, E = PV
= 101 Kpa*150m³
= 15,150 Kpa.m³ = 15,150 KJ
P*t = E
where;
t is the time required to heat this room
1 kW = 3600 kJ/h
2 kW = 7200 kJ/h
Therefore, the amount of time needed for this heating to occur is 126.25 min