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4 years ago

What is the frequency of a rubber band that vibrates back and forth 50 times in 1 second

Physics

1 answer:

ch4aika [34]4 years ago

4 0

If it makes 50 complete back-and-forth wiggles in 1 second, then its frequency is <em>50 Hz</em>.

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If, in the above diagram, no gravitational force delay the ball's movement (that is, if the right-hand side of the diagram were

viva [34]

Answer:

A or B

Explanation:

6 0

3 years ago

A runner makes one lap around a 200 m track in a time of 25.0 s. What was the runner's average speed?

creativ13 [48]

The answer is 8 meters per second 8m/s because 200 divided by 25 is 8

3 0

4 years ago

Read 2 more answers

What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo

emmainna [20.7K]

Answer:

14,300 lines per cm

Explanation:

Given that

The wavelength of visible light ranges from 400 nm to 400nm

It is possible to find the maximum number of lines per cm. This maximum number of lines per cm is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ), where

m = order of diffraction.

λ = wavelength of the incident light.

d = distance between the centers of the two slits.

θ = angle of diffraction of the mth order.

In order to find the least separation that allows the observation of one complete order of spectrum of the visible region, we make use the maximum or highest wavelength of the visible region that we are given, which is 700 nm.

d = mλ / sin (θ)

Again, we need the distance d to be the smallest, so sin (θ) must be the greatest, and for sin (θ) to be the greatest, it has to be equal to 1. Using the longest wavelength is the best idea because when the smallest wavelength is used the longest wavelength would not be diffracted.

d = mλ / sin (θ)

d = 1 * 700nm / 1

d = 700 nm

Next, we say that

n = 1/d

n = 1 / 700 x

n = 1, 430,000 lines per m, converting to cm, we have n = 14,300 lines per cm

3 0

3 years ago

The heaviest weight ever lifted by a human ear is 51.7kg. how many pounds is this?

nataly862011 [7]

Answer:

hey!

Your answer will be EXACTLY 113.97899 Pounds

Explanation:

BUT IF YOU ROUND THIS UP TO THE WHOLE NUMBER etc IT WILL BECOME 114 POUNDS!

Hope This Helped!

itsMATT04

3 0

4 years ago

An ideal spring has spring constant ks (to distinguish it from the electrostatic constant k) and equilibrium length l. Then, you

nexus9112 [7]

Answer:

q = square root (4KsL³/k)

The force of extension of the spring is equal to the force of repulsion between the two like charges. Two like charges(positive or negative) would always repel each other and two unlike charges would always attract each other. This electric force between the charges is what is responsible for the stretching of the spring. The electric force causes the spring to increase in length from L to 2L. Equating these forces, that is the electric force between the charges and the elastic force of the spring and rearranging the variables gives the expression to obtain q.

Explanation:

See the attachment below for full solution.

5 0

4 years ago