What is the frequency of a rubber band that vibrates back and forth 50 times in 1 second
1 answer:
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Answer:
the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.
Explanation:
Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:
Then, if we assign the subindex "1" to the quantities that define the magnetic field () inside solenoid 1, we have:
notice that there is no dependence on the diameter of the solenoid for this formula.
Now, if we write a similar formula for solenoid 2, given that it has :
1) half the length of solenoid 1 . Then
2) twice as many turns as solenoid 1. Then
3) three times the current of solenoid 1. Then
we obtain:
Answer:
Option B, Fix the piston in place so the volume of the pas remains constant
Explanation:
As we know
The effect on variable due to another variable can be studied by keeping the third variable constant.
Hence, in order the study the variation of temperature with pressure or vice versa, the volume needs to fixed at a certain value.
Hence, option B is correct