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4 years ago

What is the frequency of a rubber band that vibrates back and forth 50 times in 1 second

Physics

1 answer:

ch4aika [34]4 years ago

4 0

If it makes 50 complete back-and-forth wiggles in 1 second, then its frequency is <em>50 Hz</em>.

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100 POINTS!! PLEASE DONT ANSWER UNLESS YOU KNOW BOTH ANSWERS PLEASE.

JulijaS [17]

Answer:

1. is B and 2. is A

Explanation:

6 0

3 years ago

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A spring with spring constant of 26 N/m is stretched 0.22 m from its equilibrium position. How much work must be done to stretch

Evgen [1.6K]

Answer:

1.503 J

Explanation:

Work done in stretching a spring = 1/2ke²

W = 1/2ke²........................... Equation 1

Where W = work done, k = spring constant, e = extension.

Given: k = 26 N/m, e = (0.22+0.12), = 0.34 m.

Substitute into equation 1

W = 1/2(26)(0.34²)

W = 13(0.1156)

W = 1.503 J.

Hence the work done to stretch it an additional 0.12 m = 1.503 J

8 0

3 years ago

An insulated lunch bag keeps food warm by

Hatshy [7]

I believe the answer is D

4 0

3 years ago

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Is gravity a property of mass ?

Alex787 [66]

Answer:

no it is not a property of mass

5 0

3 years ago

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The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to

kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope $l = 3.10$ m

Mass of man $m = 76$ Kg

Mass of car $M = 1520$ Kg

Velocity of car $v = 1.01$ $\frac{m}{s}$

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

$\frac{1}{2} M v^{2} = mgh$

We calculate height,

$h = \frac{M v^{2} }{2mg}$

$h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}$ ( ∵ $g = 9.8 \frac{m}{s^{2} }$ )

$h = 1.05$ m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒ $3.10 - 1.05 = 2.05$

We can calculate angle between them,

$\cos \theta = \frac{2.05}{3.10} = 0.6597$

$\theta =$ 48.72°

Therefore, the angle from the vertical is 48.72°

8 0

3 years ago