It takes a resistance heater having 2 kW power to heat a room having 5 m X 5 m X 6 m size to heat from 0 to 32 oC at sea level.
1 answer:
Answer:
The amount of time needed for this heating to occur is 126.25 min
Explanation:
Given;
power required to heat the room = 2kW
volume of the room = 5 m X 5 m X 6 m = 150 m³
atmospheric pressure at sea level = 101 Kpa
Internal energy available in this room, E = PV
= 101 Kpa*150m³
= 15,150 Kpa.m³ = 15,150 KJ
P*t = E
where;
t is the time required to heat this room
1 kW = 3600 kJ/h
2 kW = 7200 kJ/h
Therefore, the amount of time needed for this heating to occur is 126.25 min
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Answer:
ANSWER BELOW I
I
V
Remember that w=mg where w is weight in Newtons, m is mass in kilograms, and g is gravity in
m/s2
. For example, for Earth, 445 N = 45.4 × 9.8
m/s2
:Notice that the x-axis values will be gravity in
m/s2
, which is already given in the table, and the y-axis values will be the weight in Newtons. Remember to round your weights to a whole number, and to enter the points starting with the lowest gravity (moon, then Mars, then Venus, then Earth).
