Answer:
![T = 29.66 ^o C](https://tex.z-dn.net/?f=T%20%3D%2029.66%20%5Eo%20C)
Explanation:
As we know that here final equilibrium temperature is 0 degree C
so we can use energy conservation here
heat given by the cube = heat absorbed by the ice
so we have
![ms \Delta T = m' L](https://tex.z-dn.net/?f=ms%20%5CDelta%20T%20%3D%20m%27%20L)
so here we have
![0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)](https://tex.z-dn.net/?f=0.220%28385%29%28T%20-%200%29%20%3D%20%287.50%20%5Ctimes%2010%5E%7B-3%7D%29%283.35%20%5Ctimes%2010%5E5%29)
![T = \frac{2512.5}{0.220 \times 385}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2512.5%7D%7B0.220%20%5Ctimes%20385%7D)
![T = 29.66 ^o C](https://tex.z-dn.net/?f=T%20%3D%2029.66%20%5Eo%20C)
“a point representing the mean position of the matter in a body or system.”
Answer:
Vmax=11.53 m/s
Explanation:
from conservation of energy
![E_A} =E_{B}](https://tex.z-dn.net/?f=E_A%7D%20%3DE_%7BB%7D)
Spring potential energy =potential energy due to elevation
0.5*k*x²= mg
=mgh
0.5*k*2.3²= 430*9.81*6
k=9568.92 N/m
For safety reason
k"=1.13 *k= 1.13*9568.92
k"=10812.88 N/m
agsin from conservation of energy
![E_A} =E_{C}](https://tex.z-dn.net/?f=E_A%7D%20%3DE_%7BC%7D)
spring potential energy=change in kinetic energy
0.5*k"*x²=0.5*m*![V_{max}^{2}](https://tex.z-dn.net/?f=V_%7Bmax%7D%5E%7B2%7D)
10812.88 *2.3²=430*![V_{max}^{2}](https://tex.z-dn.net/?f=V_%7Bmax%7D%5E%7B2%7D)
=11.53 m/s
The answer is Newton's 3rd Law. The reason why is because a force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject ofNewton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.
Answer:
- When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
- If the mass of the object was doubled, it would experience an acceleration of half the magnitude
Explanation:
When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
From Newton's second law of motion, the acceleration of the object is given as;
a = ∑F / m
a = -F / m
The negative value of "a" indicates acceleration to the left
where;
∑F is the net force on the object
m is the mass of the object
At a constant force, F = ma ⇒ m₁a₁ = m₂a₂
If the mass of the object was doubled, m₂ = 2m₁
a₂ = (m₁a₁) / (m₂)
a₂ = (m₁a₁) / (2m₁)
a₂ = ¹/₂(a₁)
Therefore, the following can be deduced from the acceleration of this object;
- When an object experiences acceleration to the left, the net force acting on this object will also be to the left.
- If the mass of the object was doubled, it would experience an acceleration of half the magnitude