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Vesna [10]
2 years ago
10

A cook puts 9.00g of water in a 2.00 -L pressure cooker that is then warmed to 500°C . What is the pressure inside the container

?
Physics
1 answer:
Lisa [10]2 years ago
3 0

If a cook puts 9.00g of water in a 2.00 -L pressure cooker that is then warmed to 500°C, the pressure inside the container is 15.8 atm.

<h3>What is the pressure inside the container?</h3>

From the ideal gas law;

PV = nRT

Where P is pressure, V is volume, n is amount of substance, T is temperature and R is the ideal gas constant (0.08206Latm/molK).

Given the data in the question;

  • Mass of water m = 9.00g
  • Volume V = 2.00L
  • Temperature = 500°C = ( 500 + 273.15)K = 773.15K
  • Pressure P = ?

First we determine the amount of water n.

We know that the molar mass of water is 18.01528 g/mol.

Hence

n = mass / molar mass

n = 9.00g / 18.01528 g/mol

n = 0.4995mol

Now, plug the values into the equation above and solve for P

PV = nRT

P = nRT / V

P = ( 0.4995mol × 0.08206Latm/molK × 773.15K ) / 2.00L

P = ( 31.6906Latm ) / 2.00L

P = 15.8 atm

If a cook puts 9.00g of water in a 2.00 -L pressure cooker that is then warmed to 500°C, the pressure inside the container is 15.8 atm.

Learn more about Ideal Gas Law here: brainly.com/question/4147359

#SPJ1

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