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4 years ago

14

How can Newton's laws be used when addressing the motion of objects?

1 answer:

romanna [79]4 years ago

6 0

They can be used to calculate state of object (moving or stationary), acceleration of the moving object, forces acting on the object & reactions of it.

You might be interested in

Given the word equation below:

gulaghasi [49]

Answer:

Sodium and water

Explanation:

We are given with the word equation :

sodium + water + sodium hydroxide + hydrogen

It is required to find that the reactants of the above equation.

In terms of chemical formula we can write it as :

$Na+H_2O\rightarrow NaOH+H_2$

Reactant of a chemical equation are the elements that are present on its LHS. These are the components of which the equation is composed of. So, the reactants of the given equation are sodium and water.

5 0

3 years ago

The production of heat by metabolic processes takes place throughout the volume of an animal, but loss of heat takes place only

Sever21 [200]

To solve this problem we will apply the concepts related to the change in length in proportion to the area and volume. We will define the states of the lengths in their final and initial state and later with the given relationship, we will extrapolate these measures to the area and volume

The initial measures,

$\text{Initial Length} = L$

$\text{Initial surface Area} = 6L^2$ (Surface of a Cube)

$\text{Initial Volume} = L^3$

The final measures

$\text{Final Length} = L_f$

$\text{Final surface area} = 6L_f^2$

$\text{Final Volume} = L_f^3$

Given,

$\frac{(SA)_f}{(SA)_i} = 2$

Now applying the same relation we have that

$(\frac{L_f}{L_i})^2 = 2$

$\frac{L_f}{L_i} = \sqrt{2}$

The relation with volume would be

$\frac{(Volume)_f}{(Volume)_i} = (\frac{L_f}{L_i})^3$

$\frac{(Volume)_f}{(Volume)_i} = (\sqrt{2})^3$

$\frac{(Volume)_f}{(Volume)_i} = (2\sqrt{2})$

$\frac{(Volume)_f}{(Volume)_i} = 2.83$

Volume of the cube change by a factor of 2.83

6 0

4 years ago

If the pressing force on the slidding surfaces is greater then friction will be

Tema [17]

Answer:

Kinetic friction is lesser than limiting friction. Two surfaces are rubbed together, first with a smaller force and then with a greater force.

3 0

3 years ago

A proton travels with a speed of 1.8×106 m/s at an angle 53◦ with a magnetic field of 0.49 T pointed in the +y direction. The ma

Likurg_2 [28]

Answer:

Magnetic force, $F=1.12\times 10^{-13}\ N$

Explanation:

It is given that,

Velocity of proton, $v=1.8\times 10^6\ m/s$

Angle between velocity and the magnetic field, θ = 53°

Magnetic field, B = 0.49 T

The mass of proton, $m=1.672\times 10^{-27}\ kg$

The charge on proton, $q=1.6\times 10^{-19}\ C$

The magnitude of magnetic force is given by :

$F=qvB\ sin\theta$

$F=1.6\times 10^{-19}\ C\times 1.8\times 10^6\ m/s\times 0.49\ Tsin(53)$

$F=1.12\times 10^{-13}\ N$

So, the magnitude of the magnetic force on the proton is $1.12\times 10^{-13}\ N$ . Hence, this is the required solution.

3 0

4 years ago

An electron enters a region of uniform perpendicular en and bn fields. it is observed that thevelocity nv of the electron is una

konstantin123 [22]

<span>v is perpendicular to both E and B and has a magnitude E/B</span>

5 0

3 years ago