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alexdok [17]
3 years ago
12

The motion of a piston in an auto engine is simple harmonic. If the piston travels back and forth over a distance of 10 cm and t

he piston has a mass of 1.5 kg, what is the maximum speed of the piston and the maximum force acting on the piston when the engine is running at 4200 rpm?
Physics
1 answer:
chubhunter [2.5K]3 years ago
3 0

Answer:

Maximum force will be 29040 N

Explanation:

We have given mass of the piston m = 1.5 kg

Amplitude A = 10 cm = 0.1 m

Angular speed \omega =4200rpm=\frac{2\times 3.14\times 4200}{60}=440rad/sec

We know that angular speed is given by \omega =\sqrt{\frac{k}{m}}

440=\sqrt{\frac{k}{1.5}}

Squaring both side

193600=\frac{k}{1.5}

k = 290400 N/m

Now force is given by F=kA=290400\times 0.1=29040N

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In lightning storms, the potential difference between the Earth and the bottom of the thunderclouds can be as high as 350MV . Th
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Complete Question

In lightning storms, the potential difference between the Earth and the bottom of the thunderclouds can be as high as 350 MV (35,000,000 V). The bottoms of the thunderclouds are typically 1500 m above the earth, and can have an area of 120 km^2. Modeling the earth/cloud system as a huge capacitor, calculate

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Answer:

a

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b

  Q =  24.78 \  C

c

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Explanation:

From the question we are told that

The potential difference is  V  =  35000000 V

The distance of the bottom of the thunderstorm from the earth is  d = 1500 m

The area is  A =  120 \  km^2 =  120 *10^{6} \  m^2

Generally the capacitance of the earth cloud system is mathematically represented as

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So

     C =  8.85*10^{-12} *  \frac{120*10^{6}}{1500}

=>  C =  7.08 *10^{-7} \  F

Generally the charge stored in the capacitor (earth-cloud system) is mathematically represented as

       Q =  C  *  V

=>    Q =  7.08 *10^{-7}  *   35000000

=>    Q =  24.78 \  C

Generally the energy stored in the capacitor is mathematically represented as

       E = \frac{1}{2}  * Q *  V

=>    E = \frac{1}{2}  *   24.78 *  35000000

=>    E =433650000 \ J

   

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