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vovikov84 [41]
1 year ago
14

If p(a | b) = 0.4, p(b) = 0.8, and p(a) = 0.5, are the events a and b independent?

Mathematics
1 answer:
pashok25 [27]1 year ago
7 0

The events A and B are not independent.

Given that,

                  P(A|B) = 0.4

                  P(A) = 0.5

                  P(B) = 0.8

Two events A and B are said to be independent, if P(A∩B) = P(A) P(B)

We have, P(A|B) = P(A∩B)/P(B)

Therefore, P(A∩B) = P(A|B) P(B) = 0.4 x 0.8 = 0.32

Now P(A) P(B) = 0.5 x 0.8 = 0.4

So P(A∩B) ≠ P(A)P(B)

Therefore, the events A and B are not independent.

Learn more about independent events at brainly.com/question/22881926

#SPJ4

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Answer:

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Step-by-step explanation:

4x-3y=8

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Is there any of the like terms can be added and the result will be 0? No, so we have to multiple one OR both of the equations to make that one number do that.

(I will try to remove the y like terms so i will multiple both of them by the opposite so both of the ys will be 6)

2(4x-3y=8)

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(now the easy part… cancel the 6s and add the equations)

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Replace x in any of the equations and you’ll get the y value.

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Given z=f(x,y),x=x(u,v),y=y(u,v), with x(4,1)=5 and y(4,1)=2, calculate zv(4,1) in terms of some of the values given in the tabl
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No table = incomplete answer
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Step-by-step explanation:

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