WILL GIVE BRAINLIST 2 BEST ANSWER slove for variable 20- = t-6 SHOW WORK

Write and equation for this table use y=mx+b PLA ANSWER HELP FAST

hodyreva [135]

Answer:

y=2/3x+19/3

Step-by-step explanation:

plug into y-y prime = m (x-x prime)

7 0

3 years ago

When Joseph first starts working at a grocery store, his hourly rate is $10. For each year he works at the grocery store, his ho

stiks02 [169]

Answer: R(t) = 10 + 0.50t

Step-by-step explanation:

From the question, we've been informed that Joseph's hourly rate is $10 and that for every year he works at the grocery store, his hourly rate increases by $0.50.

Therefore, the function will be

R(t) = 10 + 0.50t

4 0

3 years ago

A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of

Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

Hours of TV per week (X): 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean number of hours of TV watched per week = $\frac{\sum X}{n}$ = 9.65

s = sample standard deviation = $\sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }$ = 4.61

n = sample of people = 20

$\mu$ = true average number of hours of TV watched per week

Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.

So, 80% confidence interval for the true average, $\mu$ is ;

P(-1.33 < $t_1_9$ < 1.33) = 0.80 {As the critical value of t at 19 degrees of

freedom are -1.33 & 1.33 with P = 10%}

P(-1.33 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.33) = 0.80

P( $-1.33 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

P( $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X-1.33 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.33 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $9.65-1.33 \times {\frac{4.61}{\sqrt{20} } }$ , $9.65+1.33 \times {\frac{4.61}{\sqrt{20} } }$ ]

= [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0

3 years ago

Plz help find the circumference

Gemiola [76]

Answer:

π .5 in.

Step-by-step explanation:

circumference is pi times diameter

diameter is 2 times the radius

they gave u the radius which is .25 in.

so the diameter is .25×2= .5 in.

the answer is pi times .5

8 0

3 years ago

Penelope is now 3 times the age of jaslin. If jaslin will be 12 in 3 years, how many years ago was Penelope 13 years ago?

shusha [124]

Answer:

Penelope is 14 years old.

Step-by-step explanation:

- Jaslin is 9 years old (since she'll be 12 in 3 years)

- So, you multiply 9 by 3 (since Penelope is 3 times Jaslin's age), which gives you 27.

- Then minus 13 from 27 (since we're solving for how old Penelope was 13 years ago), which gives you 14

Hope this helps!

6 0

2 years ago