3x2 + 4x - 8 = 0?
1 answer:
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Answer:
(3 + 4x)(9 - 12x + 16x²) = 0
(4m - 1)(16m² + 4m + 1) = 0
Step-by-step explanation:
Here we have to solve the sum of two cubes which is
Now, the equation is
⇒ 3³ + (4x)³ = 0
⇒ (3 + 4x)[3² - 3(4x) + (4x)²] = 0
⇒ (3 + 4x)(9 - 12x + 16x²) = 0
So, (3 + 4x) = 0 or (9 - 12x + 16x²) = 0
Therefore, from the above two relation we can solve for x.
One root will be and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation.
Again, we have to solve the difference of two cubes which is
Now, the equation is
⇒ (4m)³ - 1³ = 0
⇒ (4m - 1)[(4m)² + 4m(1) + 1²] = 0
⇒ (4m - 1)(16m² + 4m + 1) = 0
So, (4m - 1) = 0 or (16m² + 4m + 1) = 0
Therefore, from the above two relation we can solve for m.
One root will be and the others we will get by applying Sridhar Acharya Formula, which will give a pair of conjugate imaginary roots of the equation. (Answer)