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andrezito [222]
2 years ago
13

The element rhenium (Re) has two naturally occurring isotopes 185Re and 187Re. Rhenium is 62.60% 187 Re (186.956 amu) and 185Re

(184.955 amu). Calculate the average atomic mass.
Chemistry
1 answer:
Gre4nikov [31]2 years ago
5 0

The average atomic mass of the element rhenium (Re) is 186.208 amu

<h3>Data obtained from the question</h3>

Ffrom the question given above, the following data were obtained:

  • Mass of isotope A = 184.955 amu
  • Mass of isotope B = 186.956 amu
  • Abundance of B = 62.60%
  • Abundance of A = 100 - 62.60 = 37.4%
  • Average atomic mass =?

<h3>How to determine the average atomic mass </h3>

The average atomic mass of the element can be obtained as illustrated below:

Average atomic mass = [(Mass of A × Abundance of A)/100] + [(Mass of B × Abundance of B)/100]

Average atomic mass = [(184.955 × 37.4)/100] + [(186.956 × 62.60)/100]

Average atomic mass = 186.208 amu

Thus, the average atomic mass of the element is 186.208 amu

Learn more about isotope:

brainly.com/question/28223231

#SPJ1

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3 years ago
The combustion of liquid methanol has a change in enthalpy of -1278 kJ. How much energy will you get from burning 245.0 g of met
Nookie1986 [14]

Answer : 9773 kJ

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Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of methanol}=\frac{245.0g}{32.04/mol}=7.647moles

Given : Change in enthalpy on combustion of 1 mole of methanol = -1278  kJ

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3 0
3 years ago
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Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

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Will be written as:

H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b)   Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)

Will be written as:

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(c)   NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)

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Thus, we can conclude that Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g) is an oxidation-reduction reaction.

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