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3 years ago

GIVING BRAINLY AND 20 POINTS

Chemistry

1 answer:

ipn [44]3 years ago

8 0

Explanation:

frequency= velocity/ wavelength

= 340/1.36

=250

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How can you tell from the name the types of bonds present in a hydrocarbon?

Darya [45]

Answer:

Alkane

Alkene

Alkyne

Explanation:

Alkane=1 bond (Saturated hydrocarbon)

Alkene= 2 bonds (Unsaturated hydrocarbon)

Alkyne= triple bonds (Unsaturated hydrocarbon)

Formula of Alkane = CnH2n+2

Formula of Alkene = CnH2n

Formula of Alkyne = CnH2n-2

7 0

3 years ago

What is the resultant pressure if 1.7 mol of ideal gas at 273 K and 2.79 atm in a closed container of constant volume is heated

dedylja [7]

Answer: The resultant pressure is 3.22 atm

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$ (At constant volume and number of moles)

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 2.79 atm

$P_2$ = final pressure of gas = ?

$T_1$ = initial temperature of gas = 273K

$T_2$ = final temperature of gas = 315 K

$\frac{2.79}{273}=\frac{P_2}{315}$

$P_2=3.22atm$

Thus the resultant pressure is 3.22 atm

6 0

3 years ago

What is a physical change

kompoz [17]

It's changing a thing with force, not chemicals, like cutting paper

8 0

4 years ago

How many protons does an atom of bromine have ?

Nostrana [21]

Each atom of bromine has 35 protons and this is bromine's atomic number. <span />

5 0

4 years ago

Read 2 more answers

Lead (II) carbonate decomposes to give lead (II) oxide and carbon dioxide: PbCO 3 (s) PbO (s) CO 2 (g) ________ grams of lead (I

blsea [12.9K]

Answer:

We will have 7.30 grams lead(II) oxide

Explanation:

Step 1: Data given

Mass of lead (II)carbonate = 8.75 grams

Molar mass PbCO3 = 267.21 g/mol

Step 2: The balanced equation

PbCO3 (s) ⇆ PbO(s) + CO2(g)

Step 3: Calculate moles PbCO3

Moles PbCO3 = mass / molar mass

Moles PbCO3 = 8.75 grams / 267.21 g/mol

Moles PbCO3 = 0.0327 moles

Step 4: Calculate moles PbO

For 1 mol PbCO3 we'll have 1 mol PbO and 1 mol CO2

For 0.0327 moles PbCO3 we'll have 0.0327 moles PbO

Step 5: Calculate mass PbO

Mass PbO = moles PbO * molar mass PbO

Mass PbO = 0.0327 moles * 223.2 g/mol

Mass PbO = 7.30 grams

We will have 7.30 grams lead(II) oxide

7 0

4 years ago