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Gnom [1K]
3 years ago
13

A metal ball has a density of 807.g/mL. If it has a volume of 0.0300L, calculate the mass of the object in grams and correct sig

figs.
Chemistry
1 answer:
scZoUnD [109]3 years ago
6 0

Answer:

24,000 grams

Explanation:

  1. 0.0300 L × 1000 ml/1 L = 30.
  2. using the d = m/v formula, we plug in 807. g/mL = m/30. L
  3. 807. × 30 = 24210.00
  4. using sig figs, the answer would be 24,000 grams (decimals: 0, sig figs: 2)
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A gas bubble has a volume of 0.650 mL at the bottom of a lake, where the pressure is
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Considering the Boyle's law, as the pressure decreases, volume increases and has a value of 2.246 mL.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

This law says that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

If an initial state 1 and a final state 2 are analyzed, Boyle's law is expressed as:

P1×V1=P2×V2

<h3>Volume at the surface of the lake</h3>

In this case, you know:

  • P1= 3.46 atm
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Replacing in Boyle's law:

3.46 atm× 0.650 mL= 1 atm×V2

Solving:

V2= (3.46 atm× 0.650 mL)÷ 1 atm

<u><em>V2= 2.246 mL</em></u>

Finally, as the pressure decreases, volume increases and has a value of 2.246 mL.

Learn more about Boyle's law:

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