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tester [92]
1 year ago
6

In variables estimation sampling, the sample standard deviation is used to calculate the?

Mathematics
1 answer:
Nikitich [7]1 year ago
3 0

The sample standard deviation is used to calculate the determine the spread of estimates for a set of observations (i.e., a data set) from the mean (average or expected value).

<h3>What is sample standard deviation?</h3>

The spread of a data distribution is measured by standard deviation. The average distance between each data point and the mean is measured.

The sample standard deviation (s) is a measurement of the variation from the expected values and is equal to the sample variance's square root.

where

s = sample standard deviation

N = the number of observations

xi= the observed values of a sample item

\overline {x}= the mean value of the observations

Learn more about simple standard deviation, refer:

brainly.com/question/26941429

#SPJ4

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You went to 23 houses trick or Treating and you get 3 pieces of Candy at each house how much candy do you have Total ?
GenaCL600 [577]

Answer:

69 Pieces of candy

Step-by-step explanation

So you get 3 pieces of candy at every house. And you do that 23 more times. We can right that out as 23*3. Which is 69.

6 0
3 years ago
An artist is creating a large conical sculpture for a park. The cone has a height of 16 m of and a diameter of 25 m. Find the vo
alexdok [17]

Answer:

The answer is B.

Step-by-step explanation:

A=3.14 x 12.5>2

A= 3.14 x 156.25 =490-.625

A= 490.625 x 16m

A= 7, 850 m3

7 0
3 years ago
I need help asap plz I will mark branlist promise
anygoal [31]

Assuming none of the factors is zero, if an odd number of the factors of a multiplication problem have negative signs, then the product will be negative. Otherwise, the product is positive.

Assuming the dividend of a division problem is non-zero, the quotient wil be negative if the signs of the dividend and divisor are differnt. Otherwise the quotient is positive.

In short, if a multiplication or division problem involves an odd number of minus signs, the result will be negative. Otherwise, the result is positive.

5 0
3 years ago
Ten percent of the engines manufactured on an assembly line are defective.
antoniya [11.8K]

Answer:

a) the probability that the first non-defective engine will be found on the second trial is 0.09

b) probability that the third non-defective engine will be found on the fifth trial is 0.00486

c) the Mean is 1.1111  and Variance is 0.1235  

d) the Mean is 3.3333and Variance is 0.3704  

Step-by-step explanation:

Firstly;

Let x be the number of trail on which the rth defective occurs

Also let the probability that an occurrence of a defective be p = 0.10

Here, x follows negative binomial distribution with parameters r and p

The probability mass function of X is as follows:

P(X = x) = [ x -1  p^r ( 1 - p)^(x-r)       ; x = r, r + 1, r + 2, ...

                 r - 1 ]

=   [ x -1  (0.10)^r ( 1 - 0.10)^(x-r)

     r - 1 ]

= [ x -1  (0.10)^r ( 0.9)^(x-r)  ..........n 1..... let this be equatio

    r - 1 ]

This represents the probability that the rth success occurs on the xth trail.  

a)

probability that the first non-defective engine will be found on the second trial?

Substitute r = 1 and x = 2 in equation 1  

P(X = 2)  = [ 2 - 1   (0.10)¹ ( 0.90 )²⁻¹

                   1 - 1 ]

= (0.10) × (0.90)

= 0.09

Therefore, the probability that the first non-defective engine will be found on the second trial is 0.09

b)

probability that the third non-defective engine will be found on the fifth trial?

So we substitute r = 3 and x = 5 in equation 1  

P(X = 5) = [ 5 - 1  (0.10)³ ( 0.90)⁵⁻³

                  3 - 1 ]

=    [ 4    (0.10)³ ( 0.9)²

      2 ]

= 0.00486

Therefore, probability that the third non-defective engine will be found on the fifth trial is 0.00486

Now the formula for the mean of the negative binomial distribution is as follows:  

Mean u = r / p    ------- let this be equation 2

The formula for the variance of the negative binomial distribution also is as follows:  

Variance α² = rq / p²   ---------- let this be equation 3

so

c)

the mean and variance of the number of trials on which the first non-defective engine is found.  

First, let the probability that non-defective engine found be p = 0.90

And q = (1 - p) = 1 - 0.90 = 0.10  

Now we substitute r = 1, p = 0.90 and q = 0.10 in equation 2 & 3simultaneously,

the mean and variances are as follows;

Mean = r/p = 1/0.90 = 1.1111

Variance = rq/p² = (1)(0.10) / (0.90)² = 0.1235  

Therefore the Mean is 1.1111  and Variance is 0.1235  

d)

the mean and variance of the number of trials on which the third non-defective engine is found  

Let the probability that non-defective engine found be p = 0.90

And q = (1 - p) = 1 - 0.90 = 0.10

Now we substitute r = 3, p = 0.90 and q = 0.10 in equation (2) and (3) simultaneously,

the mean and variances are;

Mean = r/p = 3/0.90 = 3.3333

Variance = rq/p² = (3)(0.10) / (0.90)² = 0.3704

Therefore the Mean is 3.3333 and Variance is 0.3704    

5 0
3 years ago
What is the other polynomial send help please
posledela
In mathematics, a polynomial<span> is an expression consisting of variables (also called indeterminates) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. An example of a </span>polynomial<span> of a single indeterminate x is x</span>2<span> − 4x + 7.</span>
6 0
3 years ago
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