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tester [92]
1 year ago
6

In variables estimation sampling, the sample standard deviation is used to calculate the?

Mathematics
1 answer:
Nikitich [7]1 year ago
3 0

The sample standard deviation is used to calculate the determine the spread of estimates for a set of observations (i.e., a data set) from the mean (average or expected value).

<h3>What is sample standard deviation?</h3>

The spread of a data distribution is measured by standard deviation. The average distance between each data point and the mean is measured.

The sample standard deviation (s) is a measurement of the variation from the expected values and is equal to the sample variance's square root.

where

s = sample standard deviation

N = the number of observations

xi= the observed values of a sample item

\overline {x}= the mean value of the observations

Learn more about simple standard deviation, refer:

brainly.com/question/26941429

#SPJ4

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Children of mothers who smoked during pregnancy scored nine points lower on intelligence tests at ages three and four than child
eduard

Answer:

All of the options apply.

Step-by-step explanation:

In the example given in the question, it is stated that mothers' smoking during pregnancy can affect childs' IQ and can cause lower scores on test.

All of the given options can be given as evidence for the link between smoking and lower IQ. The diet especially throughout childhood has significant effect on the development of the brain and the prefrontal cortex.

The psychological condition that the child is in, the environment in the house that he/she grows up in affects the IQ and the EQ.

The IQ can be affected by outside factors but it also has a relation with the genes that the child takes from his/her parents.

The socioeconomic status of the mother can affect the environment that the child grows up in, the people he/she interacts with and the opportunities that he/she gets to stimulate the brain in different ways to encourage growth.

I hope this answer helps.

8 0
3 years ago
How do you solve the system 3x-y z=5, x 3y 3z=-6, and x 4y-2x=12?
dlinn [17]
3x - y + z = 5 . . . (1)
x + 3y + 3z = -6 . . . (2)
x + 4y - 2z = 12 . . . (3)

From (2), x = -6 - 3y - 3z . . . (4)
Substituting for x in (1) and (3) gives
3(-6 - 3y - 3z) - y + z = 5 => -18 - 9y - 9z - y + z = 5 => -10y - 8z = 23 . .  (5)
-6 - 3y - 3z + 4y - 2z = 12 => y - 5z = 18 . . . (6)

(6) x 10 => 10y - 50z = 180 . . . (7)
(5) + (7) => -58z = 203
z = 203/-58 = -3.5

From (6), y - 5(-3.5) = 18 => y = 18 - 17.5 = 0.5
From (4), x = -6 - 3(0.5) - 3(-3.5) = -6 - 1.5 + 10.5 = 3

x = 3, y = 0.5, z = -3.5
8 0
3 years ago
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
Rama09 [41]

You can see how this works by thinking through what's going on.

 

In the first year the population declines by 3%.  So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200.  3% of 1200 is the same as .03 * 1200.  So the population at the end of the first year is 1200 - .03 * 1200.  That can be written as 1200 * (1 - .03), or 1200 * 0.97

 

What about the second year?  The population starts at 1200 * 0.97.  It declines by 3% again.  But 3% of what???  The decline is based on the population at the beginning of the year, NOT based no the original population.  So the decline in the second year is 0.03 * (1200 * 0.97).  And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year.  So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.

 

So there's a pattern.  If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.

 

So the population after x years is 1200 * 0.97x

5 0
3 years ago
PLEASE HELP... VERY URGENT... WILL GIVE BRAINLIEST!!!
lakkis [162]

Answer:

Step-by-step explanation:

a) Pythagorean theorem,

altitude² + base² = hypotenuse²

h²  + (w² - 1)² = (w² + 1)²

                    h² = (w² + 1)² - (w² - 1)²    

{Compare with (a + b)² - (a -b)² = 4ab where a =w² & b = 1}

                   h² = 4*w²*1

                   h² = 4w²

                   h=\sqrt{4w^{2}} = \sqrt{2*2*w*w} \\\\\\h = 2w

b) Area of triangle = \frac{1}{2}b*h

                               =\dfrac{1}{2}*(w^{2}-1) *2w\\\\= (w^{2}-1)*w = w^{2}*w - 1*w\\\\=w^{3}-w

c) w =2

Area of triangle = 3w = 3*2 = 6

7 0
2 years ago
Please help need for a test, same thing as last question
Sunny_sXe [5.5K]
141) d
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23) c
51) a
49) c
3 0
3 years ago
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