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lord [1]
2 years ago
5

Translate the figure 2 units left and 7 units down.

Mathematics
1 answer:
STALIN [3.7K]2 years ago
7 0

The translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

In the question, we are asked to translate the given figure 2 units left and 7 units down.

In the translation, the left-right movement implies the change in the x-coordinate, whereas the up-down movement implies the change in the y-coordinate.

For any point P(x, y) the given rule says that after translation,

P(x, y) becomes P'(x - 2, y - 7).

The coordinates of the given figure are:

A(3,9), B(5,9), C(5,2), and D(1,4).

After translation, these points can be shown as:

A(3,9) becomes A'(1,2).

B(5,9) becomes B'(3,2).

C(5,2) becomes C'(3,-5).

D(1,4) becomes D'(-1,-3).

Thus, the translation of the given figure will have vertices, <u>A'(1,2),</u> <u>B'(3,2),</u> <u>C'(3,-5),</u> and <u>D(-1,-3)</u> from the initial vertices A(3,9), B(5,9), C(5,2), and D(1,4). The figure is attached.

Learn more about translations at

brainly.com/question/1400185

#SPJ9

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Answer with explanation:

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y=8 cos x

The point of intersection of two curves are

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sinx = cos x

x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2}

When you will look between points , 0 and x=\frac{\pi}{4}\\\\y=8\sin\frac{\pi}{4}\\\\y=4\sqrt{2},the curve obtained is right angled triangle.

Now, rotate the curve that is right angled triangle along the line , y= -1, to obtain a shape similar or resembling with Right triangular prism.

Draw a circular disc in the right triangular prism , having radius =x,and small part on the triangle having length dx.dx varies from 0 to \frac{\pi}{4}.

Required volume of solid obtained

    =\int\limits^{\frac{\pi}{4}}_0 {8 \sin x} \, dx \\\\=|-8\cos x|\left \{ {{x=\frac{\pi}{4}}} \atop {x=0}} \right.\\\\=8-4\sqrt{2}

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5 0
3 years ago
Need help with trigonometry
vovangra [49]

Answer:

\sf \tan(A) & =\dfrac{9\sqrt{22}}{44}

Step-by-step explanation:

If angle C is the right angle, then side c is the hypotenuse.

Use Pythagoras' Theorem a^2+b^2=c^2 to find the length of side a:

Given:

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  • c = 13

\implies a^2+(2 \sqrt{22})^2=13^2

\implies a^2+88=169

\implies a^2=81

\implies a=\sqrt{81}

\implies a=9

<u>Tan Trig Ratio</u>

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

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  • O = side opposite angle A = a = 9
  • A = side adjacent angle A = b = 2√22

\begin{aligned}\implies \sf \tan(A) & =\dfrac{9}{2\sqrt{22}}\\\\ & =\dfrac{9}{2\sqrt{22}} \times \dfrac{\sqrt{22}}{\sqrt{22}}\\\\ & = \dfrac{9\sqrt{22}}{44} \end{aligned}

6 0
2 years ago
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butter1 times 25/12=25/12=24/12+1/12=2+1/12=2 and 1/12 stick of butter

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for 25 servings
she needs

3 and 1/8 cup flour
2 and 1/12 tsp baking powder1 and 1/24 tsp salt2 and 1/12 stick of butter2 and 1/12 cup of sugar
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