All categories

1 year ago

What is the slope of the line that passes through the point (-6, 5) and (-3, 20)?

Mathematics

2 answers:

AysviL [449]1 year ago

7 0

Slope = y2-y1 / x2-x1
Therefore = 20-5 / -3+6 = 15/3 = 5

11111nata11111 [884]1 year ago

7 0

The steps for how to find the slope between these points. Hope this helps!

You might be interested in

Which of the following demonstrates the Commutative Property of Multiplication?

Drupady [299]

Answer:

5(2a − 3) = (2a − 3) ⋅ 5

Step-by-step explanation:

Commutative Property of Multiplication is switching the order of the numbers around, and that answer demonstrates just that.

5 0

3 years ago

Read 2 more answers

PLS PLS PLS PLS PLS PLS PLS HELP MEH WITH THIS MATH PROBLEM I NEED TO GET IT RIGHT!

kozerog [31]

Answer:

Step-by-step explanation:

Any number that have the | | symbol will automatically be positive

For example

| -5.8 | = 5.8

6 0

2 years ago

Kayaks rent for $35 per day. Write an expression using the Distribbutive Property that can help you find the cost in dollars of

PSYCHO15rus [73]

5 x 3 = 15
30 x 3 = 90
15+90=105
so that person paid $105 for that day

3 0

2 years ago

What is the answer to this?

rusak2 [61]

Answer:

x= -1, y = -1

Step-by-step explanation:

-16x +24y = -8

16x -8y = -8

16y = -16

y=-1

16x = -16

x = -1

7 0

2 years ago

Read 2 more answers

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

3 years ago