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Tresset [83]
3 years ago
10

Write the quadratic equation whose roots are 6 and -2, and whose leading coefficient is 4,

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

4x^2 - 16x - 48 = 0.

Step-by-step explanation:

In a factor form it is:

4(x + 2)(x - 6) = 0

Convert to standard form:

4(x^2 - 4x - 12) = 0

4x^2 - 16x - 48 = 0.

topjm [15]3 years ago
8 0

Answer:

.,mkglhrtjkhkoj5oyo5ktj4o5yj4op5yj4w'

Step-by-step explanation:

GET SMARTER NOT HARDER MS.

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PLEASE HELP! DUE SOON!!!!
yKpoI14uk [10]

Answer: yes

Step-by-step explanation:

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2 years ago
Solve for x and explain
galben [10]
Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other

130 = x + 136
subtract 136 from both sides

x = -6
4 0
3 years ago
Read 2 more answers
An aquarium is leaking water at the rate of three quarts in 4 days.How many quarts are leaked in 1 week?How many days does it ta
Simora [160]

Answer:

\frac{21}{4} quarts

12 days

Step-by-step explanation:

Given that:

Amount of water leaked in 4 days = 3 quarts

To find:

Number of quarts leaked in 1 week?

Number of days taken for the leakage of 9 quarts of water?

Solution:

We can simply use unitary method or the ratio to find the answers of the questions asked in the statement.

As per question statement:

Amount of water leaked in 4 days = 3 quarts

Dividing by 4 on both sides:

Amount of water leaked in 1 day = \frac{3}{4} quarts

Multiplying by 7 on both sides:

Amount of water leaked in 7 days = \frac{3}{4}\times 7 = \frac{21}{4} quarts

Number of days taken for the leakage of 3 quarts = 4 days

Multiplying by 3 on both sides:

Number of days taken for the leakage of 3 \times 3 = 9 quarts = 4 \times 3 = <em>12 days</em>

6 0
3 years ago
According to the survey. there are more Andoroid (A) users than Apple (I) users
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<h2>Users tahn apple </h2>

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7 0
3 years ago
Solve the following simultaneous linear equations.<br>2x + y = 5<br>4x – 3y = -10​
Jet001 [13]

Answer:

(1/2,4)

Step-by-step explanation:

First, determine y in first equation: 2x+y=5 or  y=5-2x

replace value of y determined in first equation (5-2x) into 2nd equation    

4x-3(5-2x)=-10

4x-15+6x=10

10x=5

x=1/2

put value of x into either equation to solve for y so

2(1/2)+y=5

1+y=5

y=4

answer: x=1/2, y=4

check answer by substituting x and y into either equation:

4x-3y=-10

4(1/2)-3(4)=-10

2-12=-10

-10=-10

or

2x+y=5

2(1/2)+4=5

1+4=5

5=5

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3 years ago
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