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Ad libitum [116K]
3 years ago
12

Is 3 hours and 30 minutes more or less than 20% of a day?

Mathematics
1 answer:
Rudik [331]3 years ago
8 0
It would be less then 20%

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If the car dealer pays 85% of the base price and 75% of the installed options price from the manufacturer,
stira [4]

Answer:

$18,007,50

Step-by-step explanation:

First, you have to calculate the 85% of the base price that the dealer pays for the car:

base price: $18,750

$18,750*85%= $15,937.5

Second, you have to calculate the 75% of the installed options price that the dealer pays:

installed options price= $2,380

$2380*75%= $1,785

Third, you have to add the 85% of the base price plus the 75% of the installed options that the dealer has to pay and you also have to add the destination charge of $285:

$15,937.5+$1,785+$285= $18,007.5

According to this, the dealer has to pay $18,007.5 for the car with a base price of $18,750 and installed options price $2380  including a destination charge of $285.

7 0
3 years ago
What are the solutions?<br>8x^2-12x-23=-5​
erastova [34]

Answer:

x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

Step-by-step explanation:

Solve for x over the real numbers:

8 x^2 - 12 x - 23 = -5

Divide both sides by 8:

x^2 - (3 x)/2 - 23/8 = -5/8

Add 23/8 to both sides:

x^2 - (3 x)/2 = 9/4

Add 9/16 to both sides:

x^2 - (3 x)/2 + 9/16 = 45/16

Write the left hand side as a square:

(x - 3/4)^2 = 45/16

Take the square root of both sides:

x - 3/4 = (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

x = 3/4 + (3 sqrt(5))/4 or x - 3/4 = -(3 sqrt(5))/4

Add 3/4 to both sides:

Answer:  x = 3/4 + (3 sqrt(5))/4 or x = 3/4 - (3 sqrt(5))/4

4 0
3 years ago
the temper ire of chicken soup is 192.7 F as it cools the temperature of the soup decreases 2.3 what is the temperature of the s
ad-work [718]

The temperature of soup after 25 minutes is 135.2^{\circ}\ F

<em><u>Solution:</u></em>

The temperature of chicken soup is 192.7°F

As it cools, the temperature of the soup decreases 2.3°F per minute

Let the initial temperature be T_0

Let "t" be the time for rate of decrease

Set up an equation

Temperature = Initial temperature - decrease in temperature

Decrease in temperature = rate of decrease x time

Therefore,

T = T_0-2.3t

<em><u>To find the temperature of soup after 25 minutes, substitute t = 25</u></em>

T = 192.7 - 2.3 (25)\\\\T = 192.7 -57.5\\\\T = 135.2

Thus the temperature of soup after 25 minutes is 135.2^{\circ}\ F

5 0
3 years ago
Please help and if you can please explain it well thank you
Ksju [112]

Answer:

there is a feature on this app where u can take a picture and it will give u the answer. i would suggest trying that because it is quite useful

4 0
3 years ago
(21-6)/3 how much money each one will make
wolverine [178]

Answer:

5

answer

answer

answer

answer

3 0
3 years ago
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