Question

A walk-a-thon was held at a local middle school. These are the average distances and times for three walkers at different times during the walk-a-thon. Lakeisha: distance- 7/8 and time- 18 minutes Baydan: distance-9/10 and time- 22 minutes Madison: distance-4/5 and time- 17 minutes. If the total distance of the route was 2 miles who completed the route first? How long did it take them if they stayed at a constant rate?

Answer 1

The person that completed the 2 miles route first is Lakeisha and he did it in a time of 41.15 minutes

How to find total time from distance?

The average distances and times are as follows;

Lakeisha: distance = 7/8; Time = 18 minutes

Baydan: distance = 9/10; Time = 22 minutes

Madison: distance = 4/5; Time = 17 minutes

Formula for speed is;

Speed = Distance/Time

Speed of Lakeisha = (7/8)/18 = 0.0486 Miles per minutes

Speed of Bayden = (9/10)/22 = 0.041 Miles per minutes

Speed of Madison = (4/5)/17 = 0.047 Miles per minutes

Thus, the person that will complete the 2 miles route first is the person with the fastest speed which is Lakeisha.

Time he will take to complete the 2 miles route = 2/0.0486 = 41.15 minutes

Read more about time from distance at; brainly.com/question/17146782

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