Answer:
Denote AH as height of triangle ABC, with H lies on BC.
Applying sine theorem:
AH/AC = sin 60
=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7
=> Area of triangle ABC is calculated by:
A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611
=> Option C is correct.
Hope this helps!
:)
Answer:
D. - 1/6
Step-by-step explanation:
M + 2/3 = 1/2
M = 1/2 - 2/3
9x+39. i think i would be that
Answer:
Step-by-step explanation:
E
To calculate the distance between two points, use the Distance Formula. The Distance Formula: √((x₂ - x₁)² + (y₂ - y₁)²), where x₁, x₂, y₁, and y₂ are the x- and y-values of two given coordinates. The given coordinates are (-1, 3) and (8, 3). Let's plug them in and solve.
√((x₂ - x₁)² + (y₂ - y₁)²)
√((-1 - 8)² + (3 - 3)²)
√((-9)² + (0)²)
√(81 + 0)
√81
9
Answer:
The distance between the points (-1, 3) and (8, 3) in the coordinate plane is 9 units.
