And adopt blinks about 450 times in 30 minutes a 12 year old blinks about 150 times in 15 minutes how many more times does an ad
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Answer:
Step-by-step explanation:
This is a test of 2 population proportions. Let m and w be the subscript for men and women players. The population proportions would be pm and pw
Pm - Pw = difference in the proportion of male and female players.
The null hypothesis is
H0 : pm = pw
pm - pw = 0
The alternative hypothesis is
Ha : pm ≠ pw
pm - pw ≠ 0
it is a two-tailed test
Sample proportion = x/n
Where
x represents number of success
n represents number of samples
For men,
xm = 1027
nm = 2441
Pm = 1027/2441 = 0.42
For women,
xw = 509
nw = 1273
Pw = 509/1273 = 0.4
The pooled proportion, pc is
pc = (xm + xw)/(nm + nw)
pc = (1027 + 509)/(2441 + 1273) = 0.41
1 - pc = 1 - 0.41 = 0.59
z = (Pm - Pw)/√pc(1 - pc)(1/nm + 1/nw)
z = (0.42 - 0.4)/√(0.41)(0.59)(1/2441 + 1/1273) = 0.02/√0.0002891223
z = 1.18
Since it is a 2 tailed test, we would find the p value by doubling the area to the right of the z score to include the area to left.
Area to the right from the normal distribution table is
1 - 0.881 = 0.119
P value = 0.119 × 2 = 0.238
Since 0.05 < 0.238, we would accept the null hypothesis
Therefore, there is no sufficient evidence to conclude that that men and women have unequal success in challenging calls.
Given list of values
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}
Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}
The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43
Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)
Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1
The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U
------------------------------------------------
Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43
This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1).
A = {23, 34, 19, 10, 9, 20, 40, 43, 28, 29, 36, 13, 27, 23, 36, 37, 7}
Sort list A to get list B
B = {7, 9, 10, 13, 19, 20, 23, 23, 27, 28, 29, 34, 36, 36, 37, 40, 43}
The smallest value is 7, so the min is 7
The largest value is 43, so the max is 43
Look through list B to find the middle-most value. What you can do is cross off each pair of outer values (see figure 1 in the attached images) until you are left with the middle value
Or you can note how there are 17 values so the median is at slot 9 (there are 8 values below the median; 8 values above the median; the 8 is from 17/2 = 8.5)
Once you know the median is 27, we split the list B into two parts
The first part, we'll call it L for lower half is
L = {7, 9, 10, 13, 19, 20, 23, 23}
which is the list of all values lower or smaller than the median.
The median of list L is 16 because its the midway point between 13 and 19. We can compute (13+19)/2 = 32/2 = 16. This is the value of Q1
The upper half U is
U = {28, 29, 34, 36, 36, 37, 40, 43}
this list shows all the values larger than the median.
The value of Q3 is 36. We find the midpoint of 36 and 36 which is just 36.
The value of Q3 is the same as the median of list U
------------------------------------------------
Five Number Summary:
Min = 7
Q1 = 16
Median = 27
Q3 = 36
Max = 43
This five number summary is then used to construct the box-and-whisker plot. See figure 2 in the attached images. The diagram shows how each piece of the boxplot is put together (eg: the left edge of the box is the value of Q1).