What is the distance from Cto D? Pls help!! I will award Brainly!!

Mathematics

1 answer:

Delicious77 [7]3 years ago

4 0

You can use the distance formula
Sqroot((x2-x1)^2 + (y2-y1)^2)
(2,-1) and (5,3), use given points
Sqroot((5-2)^2 + (3-(-1))^2)
Sqroot((3)^2 + (4^2)
Sqroot(9+16) = squareroot of 25

Squareroot of 25 = 5

Solution: D. 5 units

You might be interested in

(xy^2+x)dx + ( yx^2+y )dy =0

alexira [117]

Answer:

(y^2+1)(x^2+1)=k

Step-by-step explanation:

It looks like it is possibly separatable.

Let's try.

Factor the x out on first term and factor the y out on second term:

x(y^2+1)dx+y(x^2+1)dy=0

Subtracting y(x^2+1)dy on both sides:

x(y^2+1)dx=-y(x^2+1)dy

Divide both sides by (y^2+1)(x^2+1):

x/(x^+2+1)dx=-y/(y^2+1)dy

Integrate both sides..

Use substitution u=x^2+1 and v=y^2+1...so du= 2x dx and dv=2y dy.

.5du/u=-.5dv/v

.5ln|u|=-.5ln|v|+c

Multiply both sides by 2:

ln|u|=-ln|v|+c

Plug in our substitutions :

ln|x^2+1|=-ln|y^2+1|+c

Absolute values unnecessary since insides are positive always.... also -ln(y^2+1)=ln(1/(y^2+1))

e^ on both sides:

x^2+1=k(1/y^2+1)

(y^2+1)(x^2+1)=k

6 0

3 years ago

Jenna has bought a new hybrid car. Each week for a period of seven weeks, she has noted the fuel efficiency (in miles per gallon

Leviafan [203]

Answer: 0.82 miles per gallon

Step-by-step explanation:

Given : Jenna has bought a new hybrid car. Each week for a period of seven weeks, she has noted the fuel efficiency (x) (in miles per gallon) of her car.

The results are :45 44 43 44 45 44 43

The formula to find the standard deviation is given by :-

$\sigma=\sqrt{\dfrac{\sum_{i=1}^n(x_i-\overline{x})^2}{n-1}}$