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Anni [7]
3 years ago
11

Joy bought 3/4 of quart of fruit salad and 1/3 of a quart of three bean salad. how much more fruit salad did joy buy?

Mathematics
1 answer:
kolezko [41]3 years ago
6 0
3/4 - 1/3 =
9/12 - 4/12 =
5/12 <=== there is 5/12 more fruit salad then 3 bean salad
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How many years is tween 1844 to2015
STatiana [176]
To find the number of years between 1844 to 2015 you have to subtract.

Lets say that x is the # of years in between 1844 and 2015

Then we have:
\sf{2015 - 1844 =x}

After doing the subtraction using a calculator or a pencil and paper, you get that:

\huge{\boxed{\bf{x=171}}}

So 171 years have passed from 1844 to reach to 2015.
4 0
3 years ago
Read 2 more answers
How many solutions will there be to the following equation?16x^2=100
djverab [1.8K]

Answer:

2 solutions; x=2.5     x=-25

Step-by-step explanation:

16x^2 = 100

x^2 = 100/16

x^2 = 6.25

x = (+-) sqrt 6.25

x = (+-) 2.5

4 0
3 years ago
What is the smallest solution to this equation?​
Lapatulllka [165]

Answer:

x = - 6

Step-by-step explanation:

Given

\frac{2}{3} x² = 24 ( multiply both sides by 3 )

2x² = 72 ( divide both sides by 2 )

x² = 36 ( take the square root of both sides )

x = ± \sqrt{36} ← note plus or minus

x = ± 6

solutions are x = - 6, x = + 6

The smallest solution is x = - 6

8 0
3 years ago
Help I’m stuck!!!!!!!!!
Delvig [45]
0.45 i think just into fractions
4 0
2 years ago
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How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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