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svetlana [45]
3 years ago
7

Help me asap

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer:

12x = 84

Step-by-step explanation:

7 = \frac{84}{12}

I am joyous to assist you anytime.

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1
serg [7]

Answer:

35 by 40

Step-by-step explanation:

4 0
3 years ago
What is 1000 times 20
PIT_PIT [208]
The answer is 20,000
3 0
3 years ago
Read 2 more answers
10. In the figure below, ABCD is a square. DEFC, BCGH and AEFB are all
zysi [14]

Answer:

a) As sides of squares are always equal.

So,

BC=CD

2b+CF=a+b

CF= a+b-2b

CF= a-b

b) Area of rectangle CDEF= CDxCF

=(a+b)(a-b)

=(a²-b²)

Hope it helps :-)

6 0
3 years ago
Help!<br> C + -328 = 477
krek1111 [17]
The answer for c would be 805
8 0
3 years ago
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A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
stiks02 [169]

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB =\sqrt{(9+1)^2+(-1-7)^2} units  [By distance formula : \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41} units

Width = BC = \sqrt{(-1+5)^2+(7-2)^2} units

=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}

Area = length x width

= 2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}

Hence, the  area of the rectangle is 82 sq. units .

7 0
3 years ago
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