Ok so
x - the smallest
The other 4 are : x+1, x+2, x+3, x+4
We know that sum is 120
So
x+x+1+x+2+x+3+x+4=120
Combine like terms
5x+10=120
Subtract 10 on both sides
5x=120-10
5x=110
Divide by 5 on both sides
X=22
The third number is x+2 = 22+2=24
Answer: $4 senior, $7 child
Step-by-step explanation:
(3s + 9c = 75)
8s + 5c = 67
Since the buses travel in opposite directions, the speed at which they distance themselves is the sum of their speeds.
One bus travels at speed s.
The other bus travels at speed s + 15.
The sum of the speeds is s + s + 15 = 2s + 15
speed = distance/time
distance = speed * time
366 = (2s + 15) * 2
183 = 2s + 15
168 = 2s
s = 84
The slower bus travels at 84 km/h.
s + 15 = 84 + 15 = 99
The faster bus travels at 99 km/h.
Check:
In 2 hours, the slower bus travels 2 * 84 km = 168 km
In 2 hours, the faster bus travels 2 * 99 km = 198 km
In 2 hours, the buses are 198 km + 168 km = 366 km apart.
Our answer is correct.
Answer:
6.3
Step-by-step explanation:
i had the same question for school
Answer:
<em>Gerry arrived at the bus station at 12:30 P.M.</em>
Step-by-step explanation:
From noon and 5:00 P.M. there are 5 hours.
Gerry, Dale, and Pat arrived at the bus stop within that interval, which means the sum of the times elapsed between their arrival times must be 5.
4 out of the 5 hours elapsed since Gerry and Dale's arrivals. This means there is only one hour left for twice x.
If twice x is one hour, then x is half an hour. Thus, the complete sequence of arrivals is:
Gerry arrived at the bus station at 12:30 P.M.
Dale arrived at the bus station at 4:30 P.M.
Pat arrived at the bus station at 5:00 P.M.
