The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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Answer:
100 m3
Step-by-step explanation:
2*5*10 = 10*10 *100
Answer: 4.13 x 10^4
Step-by-step explanation: You have to just count the places such as the tens all the way to the thousands which leaves you with the exponent of 4.
Add the ratios together:
5 + 2 + 1 = 8
Divide the length of NQ by that:
24/8 = 3
Multiply the ratio of NO by that/l
The ratio of NO is 5, 5 x 3 = 15
NO = 15