The first discount on a camera was 18%. The second discount was 20%. After the two discounts the price became $328. What was the
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Answer:
(a) Point estimate = 7.10
(b) The critical value is 1.960
(c) Margin of error = 0.800
(d) Confidence Interval = (6.3, 7.9)
(e) We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9
Step-by-step explanation:
Given
-- sample mean
--- sample standard deviation
--- samples
Solving (a): The point estimate
The sample mean can be used as the point estimate.
Hence, the point estimate is 7.10
Solving (b): The critical value
We have:
--- the confidence interval
Calculate the level
Divide by 2
Subtract from 1
From the z table. the critical value for is:
Solving (c): Margin of error
This is calculated as:
Solving (d): The confidence interval
This is calculated as:
Solving (d): The conclusion
We are 90% confident that the average number of hours worked by the students is between 6.3 and 7.9
ja, yo is correct, just expand that formula with your calculator
each one is 5% bigger than pevious
each one=previous+previous*5%
each one=previous*1+previous*0.05
each one=previous*(1+0.05)
each one is 1.05 times of previous
so after n years, if today year size is P then
A=final size
so ya, after 18 years, n=18 so you get
A=2067.29 microliters