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enot [183]
3 years ago
12

Which polygon is a base of the triangular prism?

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0
The answer is A and also C
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The table shows where sixth grade students at Sharonton
e-lub [12.9K]
Did you add the picture of the table? I do not see it :(
3 0
3 years ago
I need a answer AS SOON AS POSSIBLE.. thank you :}
nadezda [96]

Answer:

1. c

2. b

3. c

4. a

5. b

6. c

7. c

Step-by-step explanation:

1. to check the congrency normally distance formula is used. if the distances/ length are equal we say that sides are congurent.

2. if the slope of two lines are equal then both the lines are parallel. if the product of the slopes of two lines equal to one then lines will be perpendicular.

3. diagonals bisect or not can be checked by using midpoint formula.

4. equilateral triangle if the distance of each side is equal so, distance formula can be used.

5 0
3 years ago
Read 2 more answers
Kevin bought 3 dvds for 45.99 how much would 7 dvds cost?
Alecsey [184]

Answer:

I am pretty sure the answer would be $107.31. Sorry if I'm wrong.

Step-by-step explanation:

First you take the total of the 3 DVD's (45.99) and you divide that by 3 (number of DVD's) to get 15.33 which is called the unit price. Then, you take your unit price and multiply that by how many items you are going to buy.

45.99 / 3 = 15.33

15.33 x 7 = 107.31

6 0
3 years ago
Question 8 (5 points)<br> Simplify (tanx- secx) (tanx+ secx).<br> 1 <br> -1<br> sec^2xtan^2x<br> 0
Bond [772]

Answer:

-1.

Step-by-step explanation:

(tanx- secx) (tanx+ secx).

= tan^2 x + tanx sec x- tanx sec x - sec^2x

= tan^2 x - sec^2 x.

But sec^2 x = 1 + tan^2 x

so tan^2 x - sec^2 x = -1

4 0
3 years ago
Read 2 more answers
A car travels 2 1/3 miles in 3 1/2 minutes at a constant speed. Write an equation to represent the car travels in miles and minu
Korvikt [17]

Answer:

d = 0.666t , where d is in miles and t is in minutes.

d = 39.94h, where d is in miles and h is in hours.

Step-by-step explanation:

A car travels 2\frac{1}{3} = 2.33 miles in 3\frac{1}{2} = 3.5 minutes at a constant speed.

Let the relation between the distance (d) traveled by car in miles after traveling t minutes is d = kt ......... (1)

Now, putting d = 2.33 miles and t = 3.5 minutes in the above equation we get,

2.33 = 3.5k

⇒ k = 0.666 (Approx.)

So, the equation (1) becomes d = 0.666t. (Answer)

Let us assume that the relation between the distance (D) traveled by car in miles after traveling h hours is d = Kh ............ (2)

Now, putting D = 2.33 miles and T = 3.5/60 = 0.058 hours in the above equation, we get

2.33 = 0.058K

⇒ K = 39.94

So, the equation (2) we get, d = 39.94h (Answer)

3 0
3 years ago
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