Answer:
0.75 is it the answer
Step-by-step explanation:
Here is the problem simplified, todo this you
Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real
Answer:
<h2>n = 8</h2>
Step-by-step explanation:
Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d
a = first term of the sequence
n = number of terms
d = common difference.
Given the first element a = 2 and 22nd to be 14
T22 = a+(22-1)d = 14
a+21d = 14
Substtuting a = 2 into the equation to get d
2+21d = 14
21d = 12
d = 12/21
d = 4/7
The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;
Tn = 2+(n-1)4/7
Given Tn = 6
6 = 2+(n-1)4/7
6 = 2+4/7 n - 4/7
6-2+4/7 = 4/7 n
32/7=4/7 n
32 = 4n
n = 32/4
n = 8
Use ax^2 + bx + c = 0
ac = -8
b = 2
The factors are 4 and -2.
Plug them into the equation:
x^2 + 4x - 2x - 8
Then factorise it:
x ( x + 4) - 2 (x + 4)
so m = 4
(x + 4)^2