Answer:
False
Explanation:
namespaces can be nested. That is we can have a hierarchy of namespaces.
For examples suppose we have a namespace top. Within this we have another namespace first. At the next level we have a namespace called second. Then we have a class MyClass as a member of this namespace second. Then the complete description of the class will be as follows:
top::first::second::MyClass
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
Answer:
D) They can be accessed by any method in the same program
Explanation:
Public methods is a form of access modifier in a programming language such as Java, Phython, C#. However, unlike other types of access modifiers like Private Methods, Protected Methods etc they do not put any form of restriction on the access. Hence, in Public Methods members, methods and classes can be accessed from anywhere.
Therefore, what is true of Public Methods is that, they can be accessed by any method in the same program
Answer:
Explanation:
The following program was written in Java. It creates a loop that asks the user for numbers. If it can convert it to an integer it accepts it and adds it to the sum variable otherwise it ouputs that it is not a valid number. Once all 10 integers are added it prints the Average of the values entered.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int sum = 0;
while (count != 10) {
System.out.println("Enter a number: ");
String answer = in.nextLine();
try {
int intAnswer = Integer.parseInt(answer);
sum += intAnswer;
count += 1;
} catch (NumberFormatException e) {
System.out.println("Not a valid number.");
}
}
int average = sum / count;
System.out.println("Average: " + average);
}
}
Answer:
D is my answer to this question.
