<span>V(h 24) = 30 cm*20 cm*24 cm = 14400 cm³ = 14,4 liters</span>
<span>V(h 15) = 30 cm*20 cm*15 cm = 9000 cm³ = 9 liters</span>
<span> + 6,5 liters = + 6500 cm³ </span>
9 liters + 6,5 liters = 15,5 liters => 15,5 liters -14,4 liters = 1,1 liters
now 15500 cm³ => 1100 cm³ =1,1 liters too much !!
Answer: 1,1 liters of water overflow the container.<span>
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$630
The total perimeter is 42 and 42x15=630
Answer:
x=1, y=7
Step-by-step explanation:
y = -3x + 10 - first equation
y=-3x + 4 - second equation
rearrange the expression to
-3x-y= -10
3x-y= -4
pick an equation and simplify; lets pick the second equation
3x-y= -4
divide 3 by both sides
x=
- third equation
substitute the value of x into an equation; lets pick the first equation
-3x-y= -10
-3
- y = -10
simplify. -3 cancels 3 so we are left with
-1(-4+y)-y = -10
simplify
4-y-y= -10
4-2y= -10
subtract 4 from both sides
-2y= -10-4
-2y= -14
divide -2 by both sides
y=7
substitute the value of y, (y=7) in an equation, we are using the second equation
3x-y= -4
3x-7= -4
3x = -4+7
3x= 3
divide 3 by both sides
x=1
so the answer is x=1, y=7
Hi there!
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I believe your answer is:
4
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Here’s why:
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- I am assuming that the fraction is supposed to be the exponent.
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![64^{\frac{1}{3}}\\--------\\\rightarrow \text{Recall the exponent rule: } a^{\frac{m}{n}}=(\sqrt[n]{a})^m\\\\\\\rightarrow \sqrt[3]{64}\\\\\rightarrow \boxed{4}](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C--------%5C%5C%5Crightarrow%20%5Ctext%7BRecall%20the%20exponent%20rule%3A%20%7D%20a%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%28%5Csqrt%5Bn%5D%7Ba%7D%29%5Em%5C%5C%5C%5C%5C%5C%5Crightarrow%20%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%5Crightarrow%20%20%5Cboxed%7B4%7D)
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Hope this helps you. I apologize if it’s incorrect.
F(x)=8/x, g(x)=8/x
f(g(x)) = f(8/x)=8/<span>8/x=x,
</span>g(f(x)) =g(8/x) =8/<span>8/x=x,
so </span>f(g(x)) = g(f(x)) = x. if <span>f of x equals eight divided by x and g of x equals eight divided by x
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